3^n=27
Solve Exponent.
3^n=27
log(3n)=log(27)(Take log of both sides)
n*(log(3))=log(27)
n=log(27) / log(3)
n=3
Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran
anastassius [24]
(x; y) -> (x - 2; y + 4)
J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)
K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)
L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)
M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)
Answer:
20
Step-by-step explanation:
10 + 10
= 20
Just add units place first.
0 + 0 = 0
Then tens place.
1 + 1 = 2
So the number,
=> 20
