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2 years ago

The table below represents a linear function f(x) and the equation represents a function g(x):

1 answer:

3 0

First, lets solve f(x). g(x) is already given. Find the slope of f(x) by doing m = y2-y1/x2-x1. I'm going to use -1,-5 (1) and 0,-1 (2). -1-(-5) = 4 and 0-(-1) = 1. This means that the slope is 4 since 4/1 = 4.
Now find y intercept (b). Since we know that y=4x+b, we can solve this by plugging in an ordered pair. I will use -1,-5. -5 = 4(-1) +b. With this, we see that -5 = -4+b and b = -1 since -5 = -4-1.
Your equation for f(x) is y=4x-1.
A: The slopes are equal since both of them are 4.
B: g(x) has a greater y intercept since 3 > -1.

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3 years ago

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3 years ago

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Answer:

The answer is below

Step-by-step explanation:

Let s(t) represent the amount of salt in the tank at time t. Therefore:

ds / dt = (rate of salt flowing into the tank) - (rate of salt going out of the tank)

$\frac{ds}{dt}=[(0.08\ kg/L*6\ L/min)+(0.09\ kg/L*5\ L/min)]-(\frac{s\ kg}{1000\ L}*11\ L/min ) \\\\\frac{ds}{dt}=(0.48\ kg/min+0.45\ kg/min)-(\frac{11s}{1000}\ kg/min )\\\\\frac{ds}{dt}=0.93\ kg/min-\frac{11s}{1000}\ kg/min \\\\\frac{ds}{dt}=\frac{930-11s}{1000}\ kg/min \\\\\frac{ds}{930-11s}=\frac{1}{1000}dt\\\\Integrating:\\\\\int\limits { \frac{ds}{930-11s}} \, ds=\int\limits {\frac{1}{1000}} \, dt\\\\-\frac{1}{11}ln(930-11s)=\frac{t}{1000}+C\\\\multiply\ through\ by\ -11:$

$ln(930-11s)= - \frac{11t}{1000}+A\\\\Take \ exponential:\\\\930-11s=e^{ - \frac{11t}{1000}+A}\\\\930-11s=C_1e^{ - \frac{11t}{1000}}\\\\11s=930-C_1e^{ - \frac{11t}{1000}}\\\\s=\frac{930-C_1e^{ - \frac{11t}{1000}}}{11} \\\\To \ find\ C_1,s(0)=0.Hence:\\\\0=\frac{930-C_1e^{ - \frac{11(0)}{1000}}}{11} \\\\0=930-C_1\\\\C_1=930\\\\s(t)=\frac{930-930e^{ - \frac{11t}{1000}}}{11} \\\\s(t)=930(\frac{1-e^{ - \frac{11t}{1000}}}{11})$

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2 years ago

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denpristay [2]

Answer:

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Step-by-step explanation:

First, find the area of the rectangle

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2 years ago

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