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2 years ago

The table below represents a linear function f(x) and the equation represents a function g(x):

1 answer:

3 0

First, lets solve f(x). g(x) is already given. Find the slope of f(x) by doing m = y2-y1/x2-x1. I'm going to use -1,-5 (1) and 0,-1 (2). -1-(-5) = 4 and 0-(-1) = 1. This means that the slope is 4 since 4/1 = 4.
Now find y intercept (b). Since we know that y=4x+b, we can solve this by plugging in an ordered pair. I will use -1,-5. -5 = 4(-1) +b. With this, we see that -5 = -4+b and b = -1 since -5 = -4-1.
Your equation for f(x) is y=4x-1.
A: The slopes are equal since both of them are 4.
B: g(x) has a greater y intercept since 3 > -1.

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Classify the following triangle. Check all that apply

grandymaker [24]

Answer:

D, E

Step-by-step explanation:

All sides are not the same length so not A

Two sides are not the same length so not B

Not all angles are less than 90 so not C

All sides are different length so D

There is a right angle so E

Not all sides are greater than 90 so not F

4 0

2 years ago

What is equivalent to 35d-25

baherus [9]

Answer:

5(7d-5)

Step-by-step explanation:

taking 5 common from 35d-25

= 5(7d- 5)

7 0

3 years ago

Read 2 more answers

Find all possible values of α+

const2013 [10]

Answer:

$\rm\displaystyle 0,\pm\pi$

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma )$

factor out tanγ:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)$

divide both sides by tanαtanβ-1 and that yields:

$\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}$

multiply both numerator and denominator by-1 which yields:

$\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)$

recall angle sum indentity of tan:

$\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta )$

let α+β be t and transform:

$\rm\displaystyle \tan( \gamma ) = - \tan( t)$

remember that tan(t)=tan(t±kπ) so

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi )$

therefore when k is 1 we obtain:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi )$

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi )$

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

$\rm\displaystyle \gamma = - \alpha - \beta \pm \pi$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }$

when is 0:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 )$

likewise by Opposite Angle Identity we obtain:

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 )$

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

$\rm\displaystyle \gamma = - \alpha - \beta \pm 0$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }$

and we're done!

8 0

3 years ago

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a rectangular field is 0.45 kilometers long and 0.3 kilometers wide what is the area of the field in square meters?

bekas [8.4K]

Answer:135000

Step-by-step explanation:

5 0

3 years ago

1+1=?..............................................................

KengaRu [80]

The answer is 2
1 + 1 = 2

8 0

2 years ago

Read 2 more answers