Help please!

1 answer:

3 0

Yes. It says the sum of 2 multiplied by any number replacing the x will be less than 8.
x will need to be less than 4:
x<4

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asambeis [7]

Answer: x=4, x=-5

Step-by-step explanation:

$\frac{x}{x-4}-\frac{4}{x+5}=\frac{36}{x^2+x-20}$

Multiply everything by the LCM = (x-4)(x+5):

$\frac{x}{x-4}\left(x-4\right)\left(x+5\right)-\frac{4}{x+5}\left(x-4\right)\left(x+5\right)=\frac{36}{x^2+x-20}\left(x-4\right)\left(x+5\right)$

$\frac{x\left(x-4\right)\left(x+5\right)}{x-4} -\frac{4\left(x-4\right)\left(x+5\right)}{x+5} =\frac{36\left(x-4\right)\left(x+5\right)}{\left(x-4\right)\left(x+5\right)}$