Insects have a distinct set of characteristics which all must have if they are insects. They must have three pairs of legs (even though sometimes they may appear different as larvae, such as caterpillars), a set of mouth parts, and a head, thorax, and abdomen.
The correct answer is he's screwed because with enough training in a mock scanner, the fMRI is sure to work.
The FBI kidnapped Mike and put him in an fMRI machine to track whether he was lying or not. FBI detects lies from the flow of blood. when he is lying, his brain put more efforts and more flow of blood.
fMRI detects lies according to brain activation patterns. Its brain activation patterns shoed different from the person who is innocent.
The flow of blood in activated areas helps in tracking lies using an fMRI machine. So, during the lie detection areas highlighted if a person lies.
learn more about the fMRI machine: brainly.com/question/6231239
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I think I understand even without the picture. I'll add a picture of the Punnett Square filled in, but what you're crossing is
Tt x tt (heterozygous crossed with a homozygous recessive)
The ratio you get in the end is 2 heterozygous (Tt) and 2 homozygous (tt) offspring, so the ratio is 1:1.
So the percentage of offspring that are homozygous recessive is 50%.
The answer to this question is <span>Developmental Levels II and III
During developmental level 2 and 3, the routines and exercise SHOULD serve a certain purpose. The exercise doer should know beforehand what type of results that they wanted to achieve and structure the routines to achieve that specific goals (for example, if they wanted to focus on losing weight without gaining muscle, they should put more time in cardio)
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a) Evolutionary fitness can be characterized as a person's commitment to the cutting edge's quality pool,which is chiefly founded on the aggregate or the genotype of the individual.This principally identifies with the conceptive achievement of an organic entity.
It is fundamentally determined by the offspring that can endure and pass on the characteristics/traits.
b) Graph is already uploaded in the below attached document.
c) The population 3 will have the most elevated frequency of heterozygotes,45% of the complete population.
d) Since population 2 is as of now having a low number of heterozygotes, the occasion would totally eliminate them from the population or decreases their number
Explanation:
Frequency of animals in population 1 having both alleles 1 and 3
frequency of allele 1 =0.60
frequency of allele 3= 0.25
Frequency of both allele 1 and 3 would be allele 1 + allele 3 frequency x 100
= 0.60+0.25 X 100= 85%