All categories

3 years ago

Evaluate j/k-0.2k when j=25 and k=5

Mathematics

1 answer:

Kamila [148]3 years ago

6 0

Answer:

$4$

Step-by-step explanation:

$\frac{j}{k} - 0.2k = \frac{25}{5} - 0.2(5) = 5 - 1 = 4$

You might be interested in

Does anyone understand this?. I also have to show my work.

snow_lady [41]

Answer:

Ans A). The graph is shown.

Ans B). 18.3333 C temperature when F is 65 temperature

Ans C). 32 F when the line crosses the horizontal axis

Ans D). Slope of line C= $\frac{5}{9}(F -32)$ is $\frac{5}{9}$

Step-by-step explanation:

Given equation is C= $\frac{5}{9}(F -32)$

Ans A).

For the table,

Take the four value of F as 32,41,50,59.

For F = 32.

The value of C is

C= $\frac{5}{9}(F -32)$

C= $\frac{5}{9}(32 -32)$

C=0.

For F = 41.

The value of C is

C= $\frac{5}{9}(F -32)$

C= $\frac{5}{9}(41 -32)$

C=05

For F = 50.

The value of C is

C= $\frac{5}{9}(F -32)$

C= $\frac{5}{9}(50 -32)$

C=10

For F = 59.

The value of C is

C= $\frac{5}{9}(F -32)$

C= $\frac{5}{9}(32 -32)$

C=15

Note: The figure shows a graph of given equation with points.

Ans B). Estimate temperature in C when the temperature in F is 65

For F = 65.

The value of C is

C= $\frac{5}{9}(F -32)$

C= $\frac{5}{9}(32 -32)$

C=18.333333.

Ans C). At what temperature, graph lien cross the horizontal axis

When the line crosses the horizontal axis, C=0

Therefore,

C= $\frac{5}{9}(F -32)$

0= $\frac{5}{9}(F -32)$

0= $(F -32)$

F=32 Temperature.

Ans D). Slope of the line C= $\frac{5}{9}(F -32)$

The slope of line is given by s= $\frac{Y1-Y2}{X1-X2}$

Take points from the table of answer A.

let (32,0) and (41,5) using for slope.

s= $\frac{Y1-Y2}{X1-X2}$

s= $\frac{0-5}{32-41}$

s= $\frac{5}{9}$

Slope of line C= $\frac{5}{9}(F -32)$ is $\frac{5}{9}$

7 0

3 years ago

Can you also give me a step by step so I can learn to please.

kupik [55]

Answer:

Step-by-step explanation:

First step is Reflection over x-axis ⇒ Δ A' B' C'

Second step is Translation 2 units to the right ⇒ Δ A" B" C"

5 0

2 years ago

The diameter of a circle is 19 m. Find the circumference to the nearest tenth\textit{to the nearest tenth}to the nearest tenth.

Anna71 [15]

Answer:

361

Step-by-step explanation:

because the circumference is 19 must find the nearest tenth value is 361

8 0

2 years ago

Please help 20 points !!!! right answers please

Kamila [148]

Answer:

0.6 inch

Step-by-step explanation:

The volume of a sphere is calculated through the equation,

V = 4πr³/3

Which means that the radius is calculated by the equation,

(3V/4π)^(1/3) = r

Substituting,

Sphere A, (3x30/4π)^(1/3) = r = 1.927 in

Sphere B, (3x10/4π)^(1/3) = r = 1.336 in

When we subtract the radius, we get an answer of 0.59 inch. Therefore, the answer to this item is approximately 0.6 inch.

8 0

3 years ago

What is the value of the expression below when w=9 and x=3? 2W - 2x

Vikentia [17]

Answer:

Step-by-step explanation:

2(9)-3(3)=9

6 0

3 years ago