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2 years ago

HURRRRRRRRRRRYYY PLEASE!Brainlest

Mathematics

1 answer:

earnstyle [38]2 years ago

8 0

The scale factor is some number between 0 and 1 (not including either endpoint) because the image is smaller than the preimage.

Triangle ABC is the preimage, or the "before"; while triangle A'B'C' is the image, which is the "after".

preimage ----> image

before ----> after

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Find the value of given expression<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B2%20-%201%7D%20" id="TexFormula1" title

Bingel [31]

Answer:

Answer is 1 I hope this help

7 0

2 years ago

Read 2 more answers

Umm it’s to question just label it a and b

xxMikexx [17]

A) Scale of map is 1: 30,000

This is assuming that it meant 1 centimetre = 30,000 metres, for it gives no other information.

Multiply 1 with 30,000: 30,000 x `1 = 30,000

30,000 metres is your answer.

B) Scale is 1 inch: 6 miles. You are given 2.5 inches.

Remember that 1 inch = 6 miles.

Multiply 2.5 to both sides: (2.5) * 1 inch = (2.5) * 6 miles

2.5 inch = 2.5 * 6 miles

2.5 inch = 15 miles

15 miles is your answer.

3 0

3 years ago

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Answer step by step <br> please

Vanyuwa [196]

Answer:

the answer is D, because 30/2 is 15.

7 0

2 years ago

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A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago

A circle has an area of 2511 square centimeters. What is the length of its<br> radius?

romanna [79]

Answer:

r=28.27 cm aprox

Step-by-step explanation:

Well you know that the area of a circle is A= $\pi$ $r^{2}$ so

2511= $\pi$ $r^{2}$ so

$r^{2}$ =2511/ $\pi$

r=28.27 cm aprox

8 0

3 years ago

Read 2 more answers