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3 years ago

2x to the power 2 minus 5x+6 X=-2

Mathematics

2 answers:

Levart [38]3 years ago

8 0

Answer:

=(x-2)(x-3)

Step-by-step explanation:

This is what I got. I hope this can help you.

Bumek [7]3 years ago

5 0

(X-2)(x-3)
Step by step explanation

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The probability of Tina's winning a tennis game is 75%. What is the probability that Tina will lose a game A 10% B 25% C 50% D 7

Flauer [41]

Answer:

<u>The correct answer is B. 25%</u>

Step-by-step explanation:

If Tina's probability of winning a tennis game is 75%, therefore:

(100% - 75%) = Probability that Tina will lose a game

25% = Probability that Tina will lose a game

<u>The correct answer is B. 25%</u>

6 0

3 years ago

Need help with Geometry homework.

solmaris [256]

Answer:

SU = 22

Step-by-step explanation:

SR = RU

4x - 1 = x + 8

3x - 1 = 8

3x = 9

x = 3

SR = 4(3) - 1 = 11

RU = 3 + 8 = 11

SU = 11 + 11 = 22

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3 years ago

Arnold is writing a program for a video game for one part of the he uses the rule (x,y) (x+7,y-3) to move points on the screen A

Alex787 [66]

We are given rule

when

input is (x,y)

then output is (x+7 , y-3)

(A)

we are given

input is (-10,0)

so, x=-10 and y=0

now, we can find output

x+7=-10+7=-3

y-3=0-3=-3

so, output is (-3,-3)

(B)

we are given

input is (-7,3)

so, x=-7 and y=3

now, we can find output

x+7=-7+7=0

y-3=3-3=0

so, output is (0,0)

(C)

We know that

x+7 and y-3 are translation rules of function

so, this is function

6 0

3 years ago

I really need the answer rnn so plss helpp

3241004551 [841]

Answer: Each shape has 12 edges

Step-by-step explanation:

7 0

3 years ago

How do you simplify <img src="https://tex.z-dn.net/?f=7%5Csqrt%5B4%5D%7B80pq%5E%7B2%7Dr%5E%7B8%7D%20%20%7D" id="TexFormula1" tit

kondor19780726 [428]

Answer:

$14 ( 5)^{\frac{1}{4}} p^{\frac{1}{4}} q^{\frac{1}{2}} r^{2}$

Step-by-step explanation:

The expression to simplify in this problem is

$7\sqrt[4]{80pq^2r^8}$

Which can be rewritten as

$7(80pq^2r^8)^{\frac{1}{4}}$

Or also as

$7\cdot 80^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot (q^2)^{\frac{1}{4}} \cdot (r^8)^{\frac{1}{4}}$

Now we can apply the following rule for the calculation of the power of a power:

$(a^m)^n = a^{m\cdot n}$

So we get:

$7\cdot 80^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot q^{\frac{1}{2}} \cdot r^{2}$

Which can therefore be rewritten as

$7\cdot (2^4\cdot 5)^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot q^{\frac{1}{2}} \cdot r^{2}$

And so, we get

$7\cdot 2 \cdot ( 5)^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot q^{\frac{1}{2}} \cdot r^{2}$

which can be finally rewritten as

$14 ( 5)^{\frac{1}{4}} p^{\frac{1}{4}} q^{\frac{1}{2}} r^{2}$

6 0

3 years ago