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Paladinen [302]
3 years ago
14

Complete the following statement. ___/12 = -6

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
7 0
-72/12=-6 because the 6 is negative, the 72 has to be as well
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If f(x)=3x, what is f^-1(x)?
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Answer: -1(x)] = x

Step-by-step explanation:

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How to solve systems by elomination
Alex73 [517]

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try to get rid of one of the variables by multiplying both equations by a numbers to make the variables equal. For example if you want to get rid of the x variable and in the equation it says 3x and 2x, you would multiply the entire equation by 2 and 3 to make them both 6x and because you have to increase the entire equation by the same number to make it equal. Then you would subtract them. This would elimnate a variable. solve the remaining equation. Then continue solving the equation from there by plugging in the variable that you just got. Mark me brainliest.

Step-by-step explanation:

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2 years ago
How do you write 6x (to the 3rd power) -60x (to the 2nd power) +144x in factored form?
docker41 [41]

Answer:

<h2>6x(x-4)(x-6)</h2>

Step-by-step explanation:

I assume your expression is:

6x^3-60x^2+144x.

I'll use that information.

Factor 6x^3−60x^2+144x

6x^3−60x^2+144x

=6x(x−4)(x−6)

5 0
3 years ago
43, 45, 2, 5, 13, 11<br><br> Median - <br><br> Q1 - <br><br> Q3 - <br><br> IQR -
Gnesinka [82]

Answer:

Median- 12

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Q3- 43

IQR- 38

Step-by-step explanation:

2, 5, 11, 13, 43, 45

Put your numbers in order of least to greatest

Since there is no given median as the amount of numbers is even, find the number in between the 2 middle numbers, in this case, the number would be 12, as it is in between 11 and 13.

To find Q1 and Q3, you need to find the first and third median, which would be 5 and 43. To find the IQR, you need to subtract Q3 from Q1, which would give you 38 in this equation

5 0
3 years ago
Element X decays radioactively with a half life of 15 minutes. If there are 960 grams of Element X, how long, to the nearest ten
labwork [276]

An equation is formed of two equal expressions. It will take for the radioactive element to decay from 960 grams to 295 grams in 25.54 minutes.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The radioactive decay of an element is given by the formula,

N = N_0 \cdot e^{-\lambda t}

Given the half-life of the element is 15 minutes, therefore, we can write,

\dfrac12 =  e^{-\lambda\times 15}\\\\\ln (0.5) = -\lambda\times 15\\\\\lambda = 0.0462

Now, the time it will take for 960 grams to decay to 295 grams is,

295 = 960 \cdot e^{-0.0462 \times t}\\\\\ln (\dfrac{295}{960}) = -0.0462 \times t\\\\t = 25.54\rm\ minutes

Hence, it will take for the radioactive element to decay from 960 grams to 295 grams in 25.54 minutes.

Learn more about Equation:

brainly.com/question/2263981

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8 0
2 years ago
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