Answer:
64√2 or 64 StartRoot 2 EndRoot
Step-by-step explanation:
A 45-45-90 traingle is a special traingle. Let's say one of the leg of the triangle is x. The other one is also x because of the isosocles triangle theorem. Therefore, using the pytagorean theorem, you find that x^2+x^2=c^2. 2(x)^2=c^2. You then square root both sides and get c= x√2.
Therefore, the two legs are x and the hypotenuse is x√2. x√2=128 because the question says that the hypotenuse is 128. Solve for x by dividing both sides by √2. X=128/√2. You rationalize it by multiplying the numberator and denominator of the fraction by √2. √2*√2= 2.
X=(128√2)/2= 64√2 cm.
Since X is the leg, the answer would be 64√2
Answer:
v=3i+8j
Step-by-step explanation:
The given the vector v has an initial point (-2,-6) and a terminal point of (1,2).
To find the components of vector v, we subtract the terminal points from the initial point to obtain.
v=<1,2>-<-2,-6>
v=<1--2,2--6>
v=<1+2,2+6>
v=<3,8>
As a linear combination of the standard unit vectors.
v=3i+8j
Law of sines can be used to solve this problem:
(note - let x represent the missing side length.)
1. set up proportion.
sin 90°/25 = sin 55<span>°/x
2. solve.
(x) sin 90</span>° = (25) sin 55<span>°
(x) sin 90 </span>°/sin 90° = (25) sin 55° / sin 90<span>°
</span>
x = 20.4788011072
rounded to nearest tenth = 20.5
There isn't enough information shown to kniw
Percent is over a 100 so its 250/100
