Question

Determine the axis of symmetry for the function f(x)= -2(x + 3)2 - 5.

Answer 1

Answer:-2.125

Step-by-step explanation:

1. simplify the function

-2(x+3)2-5

(-2x-6)2-5

(-4x-12)-5

-4x-17

2. formula for axis of symmetry: -b/2a

a=-4 b=-17

-(-17)/2(-4)=17/-8=-2.125

Answer 2

Answer:

The axis of symmetry for the function f(x) is x=-3.

Step-by-step explanation:

The vertex form of a quadratic function is

$y=a(x-h)^2+k$                 .... (1)

Where, (h,k) is vertex and x=h is the axis of symmetry.

The given function is

$f(x)=-2(x+3)^2-5$           .... (2)

From (1) and (2), we get

$a=-2,h=-3,k=-5$

The axis of symmetry is

$x=h$

Substitute h=-3 in the above equation.

$x=-3$

Therefore the axis of symmetry for the function f(x) is x=-3.