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3 years ago

What should be completed first when simplifying 2(x - 3) + 6(4x + 1)?

Mathematics

1 answer:

Over [174]3 years ago

6 0

Answer:

parantheses

Step-by-step explanation:

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Urgent. There are 12 coloured counters in a bag. The counters are black, white or grey A counter is chosen at random. The probab

Nastasia [14]

Answer:

1/12

Step-by-step explanation:

Needed information

$\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}$

The sum of the probabilities of all outcomes must equal 1

Solution

We are told that the probability that the counter is not black is 3/4.

As the sum of the probabilities of all outcomes must equal 1, we can work out the probability that the counter is black by subtracting 3/4 from 1:

$\sf P(counter\:not\:black)=\dfrac34$

$\implies \sf P(counter\:black)=1-\dfrac34=\dfrac14$

We are told that the probability that the counter is not white is 2/3.

As the sum of the probabilities of all outcomes must equal 1, we can work out the probability that the counter is white by subtracting 2/3 from 1:

$\sf P(counter\:not\:white)=\dfrac23$

$\implies \sf P(counter\:white)=1-\dfrac23=\dfrac13$

We are told that there are black, white and grey counters in the bag. We also know that the sum of the probabilities of all outcomes must equal 1. Therefore, we can work out the probability the counter is grey by subtracting the probability the counter is black and the probability the counter is white from 1:

$\begin{aligned}\sf P(counter\:grey) & = \sf1-P(counter\:black)-P(counter\:white)\\\\ & =\sf 1-\dfrac14-\dfrac13\\\\ & = \sf \dfrac{12}{12}-\dfrac{3}{12}-\dfrac{4}{12}\\\\ & = \sf \dfrac{12-3-4}{12}\\\\ & = \sf \dfrac{5}{12}\end{aligned}$

7 0

2 years ago

Solve each inequality(x+4)(x-8)≥0

Stolb23 [73]

Answer: x

≤

−

≥

Step-by-step explanation:

8 0

2 years ago

Name:

Vlad [161]

Answer:

115

Step-by-step explanation:

59.50-30

=29.5

29.5/0.25=115

4 0

3 years ago

For what values of x is the expression below defined?

AleksandrR [38]

The answer is x>0 on apex for x value

4 0

2 years ago

Determine whether ∆DEF=∆JKL, given that D(2,0), E(5,0), F(5,5), J(3,-7), K(6,-7), and L(6,-2)

raketka [301]

Answer:

Yes , triangle DEF is congruent to JKL

Step-by-step explanation:

Given:

The coordinates of triangle DEF are;

D (2, 0)

E(5. 0)

F(5, 5)

and

the coordinates of triangle JKL are:

J(3, -7)

K(6, -7)

L (6, -2)

The rule of translation is used on triangle DEF to get triangle JKL:

$(x , y) \rightarrow (x+1 , y-7)$

i.e

$D (2, 0) \rightarrow (2+1 , 0-7) = (3, -7)$ = J

$E (5, 0) \rightarrow (5+1 , 0-7) = (6, -7)$ = K

$F (5, 5) \rightarrow (5+1 , 5-7) = (6, -2)$ = L

As, we know that two triangles are known as congruent if there is an isometry mapping one of the triangles to the other.

therefore, triangle DEF congruent to triangle JKL

8 0

3 years ago