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Murljashka [212]
3 years ago
6

Of 97 adults selected randomly from one city, 63 have health insurance. Create a 95% confidence interval for the true proportion

of all adults in the town who have health insurance.
Mathematics
1 answer:
Flura [38]3 years ago
5 0

Answer: 95% confidence interval would be (0.555,0.745).

Step-by-step explanation:

Since we have given that

n = 97

x = 63

So, we get that

\hat{p}=\dfrac{x}{n}=\dfrac{63}{97}=0.65

At 95% confidence interval , z = 1.96

so, Margin of error would be

z\times \sqrt{\dfrac{p(1-p)}{n}}\\\\=1.96\times \sqrt{\dfrac{0.65\times 0.35}{97}}\\\\=0.095

So, interval would be

p\pm 0.095\\\\=0.65\pm 0.095\\\\=(0.65-0.095,0.65+0.095)\\\\=(0.555,0.745)

Hence, 95% confidence interval would be (0.555,0.745).

You might be interested in
Liam's breakfast was an egg and cheese biscuit with a carton of milk. He spent a total of $5.65. Finn spent $7.65 on an egg and
ruslelena [56]

Answer:

An egg and cheese biscuit was $3.65.

Step-by-step explanation:

Liam's breakfast was:

P = E + C + M

Where:

P: total price

E: egg

C: cheese biscuit

M: carton of milk  

P = E + C + M

5.65 = E + C + M   (1)

Now, Finn's breakfast was:

P = E + C + 2*M

7.65 = E + C + 2*M   (2)      

By subtracting equation (2) from (1) we have:

7.65 - 5.65 = 2M - M

M = 2

Hence, the price of a carton of milk is $2, so by entering this value into equation (1) we can find the price of an egg and cheese biscuit:

5.65 = E + C + M

5.65 - 2 = E + C

E + C = 3.65

Therefore, an egg and cheese biscuit was $3.65.

I hope it helps you!

7 0
3 years ago
If f(x)=3x+5/x, what is f9a+2)<br><br> A. 3(a+2)+8/a+2<br> B. 3(f(a))+5/f(a)+2<br> C. 3a+5/a+2
stira [4]

Answer:

b

Step-by-step explanation:

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