Use the sum of angles's trigonometric identity formula:
cos(A+B)=(cosAcosB-sinAsinB)
x+y=4cos(t+π/6)+2sint=4(cost*cosπ/6-sint*sinπ/6)+2sint
recall that cosπ//6=√3/2, and sinπ/6=1/2:
4(cost*cosπ/6-sint*sinπ/6)+2sint=4[(√3/2)cost-(1/2)sint]+2sint
simplify:2√3cost-2sint+2sint=2√3cost
Parallel = same slope
Slope = 1/2
Y = 1/2x + b
Plug in the point
0 = -1/2 + b, b = 1/2
Solution : y = 1/2x + 1/2
The answer is A
Answer:
F(x) = -3(x + 2)² - 2
Step-by-step explanation:
In the picture attached, the graph is shown.
F(x) has the form a(x - h)² + k, where (h, k) is the vertex of the parabola. We can see in the graph that the vertex is located at (-2, -2), then F(x) = a(x + 2)² - 2. If a > 0 the parabola opens upward, if a < 0 the parabola opens downward. We can see in the graph that the parabola opens downward, then the correct answer is F(x) = -3(x + 2)² - 2