Question

the distance traveled, in meters, of a coin dropped from a tall building is modeled by the equation d(t) = 4.9t^2 where d equals the distance traveled at time t seconds and t equals the time in seconds. what does the average rate of change of d(t) from t = 3 to t = 6 represent? the coin travels an average distance of 44.1 meters from 3 seconds to 6 seconds. the coin falls down with an average speed of 14.7 meters per second from 3 seconds to 6 seconds. the coin falls down with an average speed of 44.1 meters per second from 3 seconds to 6 seconds. the coin travels an average distance of 14.7 meters from 3 seconds to 6 seconds.

Answer 1

Answer:

the answer is C: The coin falls down with an average speed of 44.1 meters per second from 3 seconds to 6 seconds.

Step-by-step explanation: i took the test and it was C. Tell me if I’m wrong

Answer 2

Average rate of change from t = 3 to t = 6 is (d(6) - d(3) )/(6 - 3) = (4.9(6)^2 - 4.9(3)^2)/3 = (4.9(36) - 4.9(9))/3 = (176.4 - 44.1)/3 = 132.3/3 = 44.1

Therefore, the coin travels an average distance of 44.1 meters from 3 seconds to 6 seconds.