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Scorpion4ik [409]
3 years ago
13

If p(x) = x2 – 1 and q(x) = 5(x-1) which expression is equivalent to (p – q)(x)?

Mathematics
2 answers:
lesya692 [45]3 years ago
6 0

Answer:

For the given expression (p-q)(x)

Option C will be correct

Step-by-step explanation:

<u>Given;</u>

       p(x) = x^2-1      

       q(x)= 5(x-1)

<u>Solution:</u>

=(p-q)(x)

=p(x)-q(x)

putting values of p(x) and q(x)          

=(x^2-1)-(5(x-1))

=x^2-1-5(x-1)

lilavasa [31]3 years ago
3 0

Answer:

Option C is correct.

The expression which is equivalent to (p-q)(x)  is, x^2 -1 - 5(x-1)

Step-by-step explanation:

Given: p(x) = x^2 -1 and q(x) = 5(x-1)

To find the expression which is equivalent to (p-q)(x):

here p and q both are function assuming;

we can write the expression :

(p-q)(x) = p(x) - q(x) = x^2 -1 - 5(x-1)

therefore, the expression which is equivalent to (p-q)(x)  is;   x^2 -1 - 5(x-1)

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1. Solve for w in the equation W/5 = 25<br> A.W = 5<br> B.W = 125<br> C. W = 30<br> D.W = 20
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