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3 years ago

13

Leng bought a television on sale for 30% off if the regular price of the set is r which expression tells the amount leng saved b

y buying at the sale price

1 answer:

kherson [118]3 years ago

5 0

Answer:

0.30 x regular price

Step-by-step explanation:

0.30 x regular price

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What is the answer X=-2(6+4)

Digiron [165]

Answer:

X = -20

Step-by-step explanation:

X = -2(6+4)

^ add 6 and 4 together first because they are in parentheses

-2(10)

^ this parenthesis means you want to multiply -2 and 10

because 2 x 10 = 20

that must mean -2 x 10 = -20

therefore, the value of X is -20

X= -20

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2 years ago

Ramon earns $1,610 each month and pays $53.40 on electricity. To the nearest tenth of a percent, what percent of Ramon's earning

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Step-by-step explanation:

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2 years ago

How can I solve 4x^2 + 12x > -x -3

Damm [24]

He have the following:

$4x^2+12x>-x-3$

solving:

$\begin{gathered} 4x^2+12x+x+3>-x-3+x+3 \\ 4x^2+13x+3>0 \\ \text{factoring} \\ (4x+1)(x+3)>0 \\ (4x+1)>0\rightarrow4x+1-1>-1\rightarrow\frac{4x}{4}>-\frac{1}{4}\rightarrow x>-\frac{1}{4} \\ (x+3)$

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11 months ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

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A large game cube is wrapped with shrinkwrap. How many square inches of shrink wrap will be used to wrap five-game cubes?

Verdich [7]

Answer:

36

Step-by-step explanation:

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3 years ago

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