Answer:
1. when there is cardiovascular disease.
2. High blood pressure increases the likelihood of suffering a stroke, a heart attack, heart failure, kidney disease or premature death.
3. The mitral valve opens.
Explanation:
1. High blood pressure is a common condition in which the force exerted by blood against the walls of the arteries over the course of time is high enough to cause you health problems such as heart disease. After the first rise of pressure caused cardiac ejection volume, one notch occurs with a second ascent product of the reflection of the pulse wave. In younger individuals, with elastic arteries, said wave occurs in diastole, so does not influence the peak systolic pressure. By contrast, with advancing age and the stiffness of large vessels, the reflected wave is transmitted prior to the aorta (systole) so as to increase the peak central PAS.
2. The pressure increases progressively the pressure of the blood flowing through the arteries. As a result, you can submit the following: Arteries damaged and narrowed. High blood pressure can damage the cells of the inner lining of the arteries.
3. When the pressure in the left ventricle falls below the pressure of the left atrium, the mitral valve opens, and the left ventricle fills with blood that had been accumulating in the left atrium.
Answer:
d. carbohydrates.
Explanation:
Sugar-consisting molecules. As a source of energy and energy storage cells employ carbs. The carbohydrates in the cells of an organism are broken down to release the stored energy.
Simple carbohydrates
Composed of one or a few molecules of sugar. Examples of simple carbs are table sugar and fruit sugar.
Complex Carbohydrates
Extra sugar from an organism may be preserved as complex hydrates of carbon. They consist of hundreds of molecules of sugar.
Answer:
1. 0% of probability, 2. 50% of probability, 3. 75% of probability.
Explanation:
In order to find the probabilities we have to draw Punnet squares. The mutated gene will be symbolized with a *.
1. Male CC with female CC, there is no mutation, the probability will be 0%.
X Y
X ║ XX ║ XY
X ║ XX ║ XY
2. The male has not got a mutation and the female has. When we draw the Punnet square, with one female X mutated, we find that there is a 50% of probability of mutation.
X Y
X* ║ X*X ║ X*Y
X ║ XX ║ XY
3. Now both, the female and the male, has the mutation. When we draw the Punnet square with mutations in the female and in the male, we find that there is a 75% of probability of mutation.
X* Y
X* ║ X*X* ║ X*Y
X ║ XX* ║ XY
