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Alex17521 [72]
3 years ago
6

Which of the following is a conjugate for 7 + iSquare root of 2?

Mathematics
2 answers:
olganol [36]3 years ago
6 0
Conjugate of a complex number a + ib = a - ib.
Therefore, conjugate of 7 + isqrt(2) = 7 - isqrt(2)
ludmilkaskok [199]3 years ago
6 0
Our complex number is:
7+i√2

Conjugate complex number is a number that has opposite sign of its imaginary part than its original. In this case imaginary part is +i√2
Conjugate value of +i√2 is -i√2 (just change the sign to opposite one)

Answer is:
7 - i√2
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Using pythagorean theorem find a, and b, where a is twice of b and the hypotonuse is 5√5
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Measure of Hypotaneous = 5√5

And it's already given that b = 2a

By using pythagoras theorem:

a²+ b² = (5√5)²

Let's substitute for b as 2a in above equation we'll get:

a² + (2a)² = (5√5)²

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a² = 25
a = √25 = 5


Therefore,
a= 5
and
b = 2a = 2(5) = 10.


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C + d = 60<br> 2.5c + 1.75d = 123.75
likoan [24]

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