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Dmitriy789 [7]
2 years ago
11

What is the minimum y-value after which the exponential function will always be greater than the linear function? y = 1 y = 3 y

= 4 y = 5
Mathematics
1 answer:
Stells [14]2 years ago
5 0

Answer:

y = 4.

Step-by-step explanation:

I suppose that this question relates to the image that can be seen below.

In the image, the green line represents the exponential function and the blue line represents the linear function.

The y-value after which the exponential function will always be greater than the linear function is the y-value where bot graphs intersect, such that after that point, the blue line starts increasing fast, and is always above the green line.

In this case, this point is the second intersection, and we can see that this intersection happens in the point (2, 4)

Remember that the usual notation for points is (x, y).

Then the y-value after which the exponential function will always be greater than the linear function is y = 4.

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Answer:

y=4

Step-by-step explanation:

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3 years ago
If AB = 3 centimeters, and BC = 4 centimeters, which does AC equal? of a triangle
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If it is a right triangle and AC is the hypotenuse, then AC is 5.
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Trig help please!!! This is due tomorrow. If you don’t mind could you please explain how you do it
vivado [14]

Answer:

The larger acute angle is equal to 50.8 degrees.

Step-by-step explanation:

Let's solve for both of the acute angles for the purpose of checking our work at the end with angle A being the top angle and angle B being the one on the base of the triangle (that's not the 90 degrees one). Determining whether to use sin/cos/tan comes from SOH-CAH-TOA.

A = cos^-1 (2√6/2√15)

However, you need to move the radical out of the denominator by multiplying √15 to the numerator and denominator. You should come up with (2√90)/30. So,

A = cos^-1 (2√90/30) = 50.768 degrees.

B = sin^-1 (2√90/30) = 39.231 degrees.

Now, we can check the work by adding the 2 angles to 90 and, if it comes to 180, it's right.

cos^-1 (2√90/30) + sin^-1 (2√90/30) + 90 = 180.

If you have any questions on where I got a formula or any step, feel free to ask in the comments!

8 0
3 years ago
I need help with exercises 3,4, and 6 please show all work and don’t answer number 5 just tell me if it is correct
joja [24]
*If you need me to do #5, DM me!

3. 
The area of a triangle can be given by (just plug and chug as always):
A_t = \frac{1}{2} bh = \frac{1}{2}(3)(4) = 6ft^2
The area of the triangle is 6ft².

4. I will divide into a triangle and a rectangle (because the actual equation for the area of a pentagon requires it to be a perfect pentagon). Let's do the triangle first (height is 3 because you subtract 12 from 15):
A_t = \frac{1}{2} bh = \frac{1}{2}(8)(3) = 12m^2
A_r = bh = 12(8) = 96m^2
Now we just add them:
96+12 = 108m^2

So, the area of that pentagon is 108m².

5. You are actually wrong on this one because the area of a triangle is:
A_t = \frac{1}{2}bh
So, just halve your answer and it will be correct.

6. We can just split it into 4 triangles of equal area and then multiply the area of 1 triangle by 4 to get the total area. Let's do just that:
A_t = \frac{1}{2}bh = \frac{1}{2}(2.5)(5) = 6.25cm^2
Multiply by 4 to get total area:
6.25*4 = 25cm^2

So, the area of the given rhombus is 25cm².
8 0
3 years ago
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