What is an expression that uses partial products to multiply 8 x 64

Which equation represents a line that passes through (-2, 4) and has a slope of 1/2?

jok3333 [9.3K]

Answer:

$\large\boxed{y-4=\dfrac{1}{2}(x+2)\text{- point-slope form}}\\\boxed{y=\dfrac{1}{2}x+5\text{- slope-intercept form}}$

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

We have the slope $m=\dfrac{1}{2}$ and the point $(-2, 4)$ .

Substitute:

$y-4=\dfrac{1}{2}(x-(-2))$

$y-4=\dfrac{1}{2}(x+2)$ - point-slope form

Convert to the slope-intercept form (y = mx + b):

$y-4=\dfrac{1}{2}(x+2)$ <em> use the distributive property</em>

$y-4=\dfrac{1}{2}x+1$ <em>add 4 to both sides</em>

$y=\dfrac{1}{2}x+5$ - slope-intercept form

3 0

2 years ago

a professor must randomly select 4 students to participate in a mock debate. There are 20 students in his class. In how many dif

Feliz [49]

If the order doesn't matter the it's
$C(20,4)=\dfrac{20!}{4!16!}=\dfrac{17\cdot18\cdot19\cdot20}{2\cdot3\cdot4}=4845$

6 0

3 years ago

Read 2 more answers

Which equation represent the graphed function

UkoKoshka [18]

Answer:

C

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (0, - 2) and (x₂, y₂ ) = (4, - 1) ← 2 points on the line

m = $\frac{-1+2}{4-0}$ = $\frac{1}{4}$

note that the line crosses the y-axis at (0, - 2) ⇒ c = - 2

y = $\frac{1}{4}$ x - 2 ← equation of line

6 0

2 years ago

Read 2 more answers

This is part 2 of my question! but the questions are marked as odds for this part, which is part 2.

Yakvenalex [24]

19) 15 <= 9 + 3x

15) x = 23,24,25

17) x <= 115

9) Second line

11) g > 20, don't fill in dot, any number greater than 20

1) -3 + h<= 3.4

3) No, x > -2

5) x > 14, don't fill in dot, any number greater than 14

7) k<=20, fill in dot, 20 or any larger number

(took me while to type this out lol cause on mobile)

5 0

1 year ago

Assume that the amount of beverage in a randomly selected 16-ounce beverage can has a normal distribution. Compute a 99% confide

ioda

Answer:

The question is incomplete, but the step-by-step procedures are given to solve the question.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.005 = 0.995$ , so Z = 2.575.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 2.575\frac{\sigma}{\sqrt{n}}$

The lower end of the interval is the sample mean subtracted by M.

The upper end of the interval is the sample mean added to M.

The 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (lower end, upper end).

7 0

2 years ago