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3 years ago

What is an expression that uses partial products to multiply 8 x 64

Mathematics

1 answer:

Ivahew [28]3 years ago

7 0

Ur answer to this question would be 512.

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Explain how you might use the properties of multiplication to solve 5 × 120 × 6.232 mentally. Then solve.

zysi [14]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

In this question, we apply the associative property that calculates the given value, which can be defined as follows:

Rule:

$\bold{\to (A\times B)\times C= A \times (B\times C)}$

Let,

$A= 5\\B=120\\C=6.232$

put the value in the above rule:

Solve L.H.S part:

$\to (5\times 120)\times 6.232\\\\\to (600)\times 6.232\\\\\to 3,739.2$

Solve R.H.S part:

$\to 5 \times (120 \times 6.232)\\\\\to 5 \times 747.84\\\\\to 3,739.2$

So, L.H.S=R.H.S

6 0

3 years ago

If ∠C and ∠D are vertical angles and m ∠ C = x + 5 and m ∠ D = –2x + 80, what is m ∠ C?

amm1812

Answer:

m∠C=30°

Step-by-step explanation:

we know that

<u>Vertical Angles</u> are the angles opposite each other when two lines cross. They are always equal

m∠C=m∠D

substitute the given values

$(x+5)\°=(-2x+80)\°$

Solve for x

$x+2x=80-5\\3x=75\\x=25$

<em>Find the measure of angle C</em>

m∠C=(x+5)°

substitute the value of x

m∠C=(25+5)=30°

3 0

3 years ago

Nathan wants to use coordinate geometry to prove that the opposite sides of a rectangle are congruent. He places parallelogram A

valentina_108 [34]

<h3><u>Answer:</u></h3>

The formula determine the distance from C to D is:

$\sqrt{(0-a)^2+(-b)^2}=\sqrt{a^2}=a$

<h3><u>Step-by-step explanation:</u></h3>

The formula that can be used to determine the distance from point C to point D is:

$\sqrt{(0-a)^2+(-b)^2}=\sqrt{a^2}=a$

We know that distance between two points A(a,b) and B(c,d) is equal to the length of the line segment AB and is calculated by the help of the formula:

$\sqrt{(c-a)^2+(b-d)^2}$

So, here we have:

(a,b)=(a,b) and (c,d)=(0,b)

3 0

3 years ago

This is a hard one for me. Can someone solve this one.

asambeis [7]

Answer:

100

Step-by-step explanation:

3 0

3 years ago

Elimination method: ax+by=r, -bx+cy=s

Alex17521 [72]

$\left[\begin{array}{ccc}ax+by=r\\\\-bx+cy=s\end{array}\right]$

Isolate x for $ax+by=r$

$x= \frac{r-by}{a} ; a \neq 0$

Subsititute $x= \frac{r-by}{a}$

$-b \frac{r-by}{a} +cy=s$

Isolate r for : $-b \frac{r-by}{a}+cy=s$

$r=- \frac{as-acy-b^2y}{b} ; a \neq 0;b \neq 0$

For x : $\frac{r-by}{a}$

Subsititute r = $- \frac{as-acy-b^2y}{b}$

$x= -\frac{as-acy-b^2y}{b}/a$

$x = \frac{cy-s}{b}$

The solutions to the system of equations are:

$r= -\frac{as-acy-b^2y}{b}$ and <span> $x = \frac{cy-s}{b}$
</span>
hope this helps!

3 0

3 years ago