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3 years ago

What is the surface area of this design??please help

Mathematics

1 answer:

Pani-rosa [81]3 years ago

3 0

Answer: 440

Step-by-step explanation:

5 * 5 = 25

8 * 5 = 40

40 * 4 = 160

160 + 25 = 185

10 * 10 = 100

100 - 25 = 75

10 * 2 = 20

20 * 4 = 80

75 + 100 + 80 + 185 = 440

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icang [17]

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4 0

3 years ago

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(555.28-122.57*(4))-(585.34-136.71*(4))

mamaluj [8]

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7 0

3 years ago

Read 2 more answers

Please help me:(***********

jeka94

Answer:

A:

Square

Rectangle

Parallelogram

Quadrilateral

Rhombus

Step-by-step explanation:

All sides and angles are equal so it is a square

All angles are 90 degrees so it is a rectangle (eliminate C)

Opposing angles and side lengths are congruent so it is a parallelogram (eliminate D)

It has 4 sides so it is a quadrilateral (eliminate B)

Since all of the other answers are eliminated you don't necessarily need to prove that is is a rhombus, but it is good practice.

Opposing sides are congruent so it is a rhombus.

4 0

3 years ago

A survey asked 40 students If they play an instrument and if they are in band.

wel

Answer:

352x^2

Step-by-step explanation:

40\times 1.25x\times 2.20x\times 3.2040×1.25x×2.20x×3.20

(40)1.25x2.20x3.20

+ − . ln > <

× ÷ / log ≥ ≤

( ) logx = %

1 Take out the constants.

(40\times 1.25\times 2.20\times 3.20)xx(40×1.25×2.20×3.20)xx

2 Simplify 40\times 1.2540×1.25 to 5050.

(50\times 2.20\times 3.20)xx(50×2.20×3.20)xx

3 Simplify 50\times 2.2050×2.20 to 110110.

(110\times 3.20)xx(110×3.20)xx

4 Simplify 110\times 3.20110×3.20 to 352352.

352xx352xx

5 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x

a+b

352{x}^{2}352x

Done

3 0

3 years ago

Write the standard form equation of the ellipse shown in the graph, and identify the foci.

vlada-n [284]

Answer option A

From the given graph is a Vertical ellipse

Center of ellipse = (-2,-3)

Vertices are (-2,3) and (-2,-9)

Co vertices are (-6,-3) and (2,-3)

The distance between center and vertices = 6, so a= 6

The distance between center and covertices = 4 , so b= 4

The general equation of vertical ellipse is

$\frac{(x-h)^2}{b^2} + \frac{(y-k)^2}{a^2}=1$

(h,k) is the center

we know center is (-2,-3)

h= -2, k = -3 , a= 6 and b = 4

The standard equation becomes

$\frac{(x+2)^2}{4^2} + \frac{(y+3)^2}{6^2}=1$

$\frac{(x+2)^2}{16} + \frac{(y+3)^2}{36}=1$

Foci are (h,k+c) and (h,k-c)

$c=\sqrt{a^2-b^2}$

Plug in the a=6 and b=4

$c=\sqrt{6^2-4^2}$

$c=\sqrt{20}$

$c=2\sqrt{5}$ , we know h=-2 and k=-3

Foci are $(-2,-3+2\sqrt{5})$ and $(-2,-3-2\sqrt{5})$

Option A is correct

6 0

3 years ago