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4 years ago

15

Uranium mining is not very disruptive of the land, and therefore nuclear power is much more desirable than coal mining. TRUE FAL

SE

2 answers:

erik [133]4 years ago

5 0

The answer to your question is True.
Hope this helped...even though your question has been answered seven days later.
Better late than never xD

Sholpan [36]4 years ago

3 0

I just took this test and im from k12 the answer is false not true. I chose true at first but it turned out to be wrong so its false

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A neutron is confined in a one-demensional potential box of width 5.0 x 10^-15 m. Calculate the minimum kinetic energy of the ne

kvv77 [185]

Answer:

$E_1=1.31\times 10^{-12}\ J$

Explanation:

Given that,

Width of a one dimensional potential box, $x=5\times 10^{-15}\ m$

The energy of a particle in one dimensional box is given by :

$E_n=\dfrac{n^2h^2}{8mx^2}$

h = Planck's constant

m = the mass of the proton

For minimum kinetic energy, n = 1

$E_1=\dfrac{(6.63\times 10^{-34})^2}{8\times 1.67\times 10^{-27}\times (5\times 10^{-15})^2}$

$E_1=1.31\times 10^{-12}\ J$

So, the minimum kinetic energy of the neutron is $1.31\times 10^{-12}\ J$ . Hence, this is the required solution.

8 0

3 years ago

A baseball travels 50 meters in 4 seconds what is the average velocity of the baseball?

beks73 [17]

The average velocity is 12.5 meters per second

5 0

3 years ago

In each of the parts of this question, a nucleus undergoes a nuclear decay. Determine the resulting nucleus in each case.

MA_775_DIABLO [31]

A) Francium-223

In an alpha decay, a nucleus decay emitting an alpha particle, which corresponds to a nucleus of helium: so, it consists of 2 protons and 2 neutrons.

$X \rightarrow X' + \alpha$

This means that in the decay:

- The original nucleus loses 2 protons --> so its atomic number Z decreases by 2 units

- The original nucleus loses 2 nucleons (2 protons and 2 neutrons) --> so its mass number A decreases by 4 units

In this example, the original nucleus is Ac (Actinium), with

Z = 89

A = 227

After the decay, it must be

Z - 2 = 89 - 2 = 87

A - 4 = 227 - 4 = 223

We see from the periodict table, Z=87 corresponds to Francium (Fr), so the final nucleus will be francium-223 (the isotope of francium with 223 nucleons).

B) Polonium-211

In a beta-minus decay, a neutron in the nucleus turns into a proton, emitting a fast-moving electron (the beta particle) and an anti-neutrino.

$n \rightarrow p + e^- + \bar{\nu}$

Therefore, in this process:

- The original nucleus gains 1 protons, so its atomic number Z increases by 1 unit

- The original nucleus does not lose/gain nucleons, so its mass number A remains the same

In this example, the original nucleus is Bi (bismuth)-211, with

Z = 83

A = 211

So After the decay, it will be

Z + 1 = 83 + 1 = 84

A = 211

So, the nucleus will be Polonium (Z=84), isotope with 211 nucleons.

C) Neon-22

In a beta-plus decay, a proton in the nucleus turns into a neutron, emitting a fast-moving positron (the beta particle) and a neutrino.

$p \rightarrow n + e^+ +\nu$

Therefore, in this process:

- The original nucleus loses 1 protons, so its atomic number Z decreases by 1 unit

- The original nucleus does not lose/gain nucleons, so its mass number A remains the same

In this example, the original nucleus is Na (sodium)-22, with

Z = 11

A = 22

So After the decay, it will be

Z - 1 = 11 - 1 = 10

A = 22

So, the nucleus will be Neon (Z=10), isotope with 22 nucleons.

D) Technetium-98

In a gamma decay, an unstable nucleus emits a gamma ray:

$X' \rightarrow X + \gamma$

In this process, only energy is released (in the form of gamma ray), so there is no gain/loss of protons/neutrons in the process. This means that:

- The atomic number Z remains constant

- The mass number A remains constant

In this example, we have a nucleus of Tc (Technetium)-98, with

Z = 43

A = 98

These numbers will not change during the decay: this means that after the decay, we will still have a nucleus of Technetium-98.

8 0

4 years ago

Can you think of any common ""real-life"" situations in which an understanding of conservation would allow a concrete operationa

Marina86 [1]

Conservation is the understanding that the quantity of an object stays the same even when it changes in appearance. A concrete operational child between ages seven and eleven understands this fact because of the development of his cognitive ability while a preoperational child does not.

For example, change the tea cup of a 5 year old boy from an oblong shape to a short round shape of the same size, he begins to cry because he believes the change in cup has translated to a change in quantity.

In addition, change the denominations contained in an amount of money owned by each of the children of these two categories, the pre operational child seems a lot bothered, but the concrete operational child has enough knowledge of conservation to be undisturbed by this re-arrangement.

3 0

3 years ago

An ideal gas, initially at a pressure of 11.2 atm and a temperature of 299 K, is allowed to expand adiabatically until its volum

Tju [1.3M]

Answer:

The pressure is $P_2 = 4.25 \ a.t.m$

Explanation:

From the question we are told that

The initial pressure is $P_1 = 11.2\ a.t.m$

The temperature is $T_1 = 299 \ K$

Let the first volume be $V_1$ Then the final volume will be $2 V_1$

Generally for a diatomic gas

$P_1 V_1 ^r = P_2 V_2 ^r$

Here r is the radius of the molecules which is mathematically represented as

$r = \frac{C_p}{C_v}$

Where $C_p \ and\ C_v$ are the molar specific heat of a gas at constant pressure and the molar specific heat of a gas at constant volume with values

$C_p=7 \ and\ C_v=5$

=> $r = \frac{7}{5}$

=> $11.2*( V_1 ^{\frac{7}{5} } ) = P_2 * (2 V_1 ^{\frac{7}{5} } )$

=> $P_2 = [\frac{1}{2} ]^{\frac{7}{5} } * 11.2$

=> $P_2 = 4.25 \ a.t.m$

8 0

3 years ago