An ideal gas, initially at a pressure of 11.2 atm and a temperature of 299 K, is allowed to expand adiabatically until its volum
1 answer:
Answer:
The pressure is
Explanation:
From the question we are told that
The initial pressure is
The temperature is
Let the first volume be Then the final volume will be
Generally for a diatomic gas
Here r is the radius of the molecules which is mathematically represented as
Where are the molar specific heat of a gas at constant pressure and the molar specific heat of a gas at constant volume with values
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4.) Quantitative: notice the root word 'quantity', which is a certain percentage of something.
a.) Quantitative, since it represents a certain percentage. The weight before the camp could also be written as an improper fraction.
b.) This is also quantitative because it can be written as a ratio, which can also be written as a fraction
or percentage.
c.) This is qualitative. Joan has a higher percentage than Emile.
d.) Qualitative. It judges the quality of something instead of amount. To make it quantitative requires a fraction of percentage. In this case, maybe you could add how he can run y miles every x seconds.
5.)
a.)This depends on whether or not the air is moving. If the classroom's AC is on, or the window is open, then the correct unit to use is CFM (cubic feet per minute). If not, the common unit is milliliters, but must also include temperature and air pressure as well as the volume of the room.
b.) Simply calculate the volume of the can using inches cubed, since volume is the measure of how much space an object takes up.
c.) The unit would be . If
, then simply multiply your density by your mass.
d.) I personally would use centimeters. Inches would work too, but centimeters would be much more accurate.
e.) Use the same formula for c.), which means kilograms per cubic foot.
Hope this helped.
Answer:
Compression in the spring, x = 3.7 cm
Explanation:
It is given that,
Mass of the book, m = 1.6 kg
It can be assumed the spring constant of the spring is, k = 840 N/m
As the book moves down, the change in potential energy of the book is converted to spring potential energy of compression. The mathematical expression is as follows :
x = 0.037 meters
or
x = 3.7 cm
So, the spring is compressed to a distance of 3.7 cm. Hence, this is the required solution.
Answer:
W = (F1 - mg sin θ) L, W = -μ mg cos θ L
Explanation:
Let's use Newton's second law to find the friction force. In these problems the x axis is taken parallel to the plane and the y axis perpendicular to the plane
Y Axis
N - =
N = W_{y}
X axis
F1 - fr - Wₓ = 0
fr = F1 - Wₓ
Let's use trigonometry to find the components of the weight
sin θ = Wₓ / W
cos θ = W_{y} / W
Wₓ = W sin θ
W_{y} = W cos θ
We substitute
fr = F1 - W sin θ
Work is defined by
W = F .dx
W = F dx cos θ
The friction force is parallel to the plane in the negative direction and the displacement is positive along the plane, so the Angle is 180º and the cos θ= -1
W = -fr x
W = (F1 - mg sin θ) L
Another way to calculate is
fr = μ N
fr = μ W cos θ
the work is
W = -μ mg cos θ L