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omeli [17]
3 years ago
7

A sheet of paper has dimensions of 8.5 in x 11 in. If you cut 2 in2 from each corner of the sheet, what will the area of the she

et of paper be?
Mathematics
2 answers:
MissTica3 years ago
7 0
The piece of paper has 4 corners.
If you cut 2 in.^2 from each corner, you are taking out 8 in.^2 of area.
The area of the uncut sheet is 8.5 in. * 11 in. = 93.5 in.^2
93.5 in.^2 - 8 in.^2 = 85.5 in.^2
anyanavicka [17]3 years ago
4 0

Answer:   85.5\ in^2

Step-by-step explanation:

Given : A sheet of paper has dimensions of 8.5 in x 11 in.

Then, the area if the sheet of paper will be :_

\text{Area}=8.5\times11=93.5\text{ in.}^2

Also, we cut 2 in^2 from each corner of the sheet.

Since, there are 4 corner in a sheet , then the combined area we cut will be :-

4\times2=8\ in.^2

Now, the area of the sheet of paper will be  =93.5\text{ in.}^2-8\text{ in.}^2

=85.5\ in^2

Hence, the area of the sheet of paper will be 85.5\ in^2

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Answer:

Step-by-step explanation:

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Whereas the basic formula for the area of a rectangular shape is length × width, the basic formula for volume is length × width × height.

In the real world, calculating volume is probably not something that you will use as often as calculating area.

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2 years ago
Evaluate the function rule for the given value f(x)=15x for x=3
lesya692 [45]

Answer:

f(3) = 45

Step-by-step explanation:

Substitute x = 3 into f(x) and evaluate

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7 0
3 years ago
Read 2 more answers
Mohit pays rupees 9000 as an amount on the sum of rupees 7000 that he had borrowed for 2 years.
Sphinxa [80]

Answer:

The required rate of interest   =   14.285%

Step-by-step explanation:

Here, The principal amount = 7,000

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Let us assume the rate of interest = R

Now, Simple Interest  =  Amount - Principal

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So, the SI on the given principal for 2 years  = 2,000

\textrm{SIMPLE INTEREST } = \frac{P \times  R \times T}{100}\\\implies 2000 = \frac{7,000 \times  R \times 2}{100}\\\implies R = \frac{2,000 \times 100}{7,000 \times 2}  = 14.285

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3 years ago
A meteorologist who sampled 4 thunderstorms found that the average speed at which they traveled across a certain state was 16 mi
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Answer:

The  90 % confidence  interval  for the mean population is (11.176  ; 20.824 )

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