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2 years ago

What is the IQR for the box plot below? (Interquartile range)

Mathematics

2 answers:

pshichka [43]2 years ago

5 0

Answer:

Step-by-step explanation:

IQR=10-6=4

olga2289 [7]2 years ago

3 0

Answer:

Step-by-step explanation:

The IQR of a box plot is $Q_{3} - Q_{1}$ .

From the box plot, the first quartile, $Q_{1}$ , is at $6$ , and the third quartile, $Q_{3}$ , is at $10$ , so the IQR is

$Q_{3} - Q_{1}$

$10 - 6$

$4$

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Ahh help plss!! thank u

AnnZ [28]

Basically you’re multiplying them both
(x^3 + 2x - 1)(x^4 - x^3 + 3)

so you need to make sure you multiply each one, if you do it right, you should end up with
x^7 - x^6 + 3x^3 + 2x^5 - 2x^4 + 6x -x^4 +x^3 -3

simplify by adding like terms
x^7 - x^6 + 2x^5 - 3x^4 + 4x^3 + 6x - 3

your answer would be the third option

4 0

2 years ago

Shelly bought 7 boxes of fish food and 2 packets of cat food. Each box of fish food contained 6 pouches, and each packet of cat

AfilCa [17]

Answer: 34 more pouches

7 boxes - fish food; 1 box contained 6 pouches

Total amount of fish food is 7 × 6 = 42 pouches of fish food

2 packets - cat food; 1 packet contained 4 pouches

Total amount of cat food is 2 × 4 = 8 pouches

How many more pouches of fish food than cat food did Shelly buy?

42 pouches - 8 pouches = 34 pouches

Therefore there was 34 more pouches of fish food than cat food

7 0

2 years ago

Which expression is equivalent to 3 (5x – 4)?

finlep [7]

Answer: 15x - 12

Steps: 3 (5x - 4)
3 x 5x - 3 x 4
15x - 3 x 4
15x - 12

6 0

3 years ago

What is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

LenKa [72]

${\bold{\red{\huge{\mathbb{QUESTION}}}}}$

what is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

$\bold{ \red{\star{\blue{GIVEN }}}}$

TOTAL NUMBER OF ARTICLE= 7

ARTICLES FOR 30K = 3

ARTICLES FOR 12.5K = 7-3= 4

$\bold{\blue{\star{\red{TO \: \: FIND}}}}$

Average cost of 7 articles

$\bold{ \green{ \star{ \orange{FORMULA \: USED}}}}$

$\red{AVERAGE = \frac{TOTAL \: COST}{ NUMBER \: OF\: ARTICLES }}$

$\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}$

$Average \: cost \: of \: 7 \: articles - > \\ \frac{(3 \times 30k) + (12 .5k \times 4)}{7} \\ \frac{90k + 50k}{7} \\ \frac{140k}{7} \\ \blue {Average \: cost \: of \: 7 \: articles - >} \\ 20k$

5 0

2 years ago

Is the function linear or quadratic?

fgiga [73]

It is quadratic since a quadratic function is of the form :y=ax²+bx+c ,a,b,c are constants.

7 0

3 years ago