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Eva8 [605]
4 years ago
8

Given: ΔABC ≅ ΔEDF

Mathematics
2 answers:
V125BC [204]4 years ago
4 0

we know that

the triangle ABC and triangle EDF are congruent triangles-----> given problem

therefore

AC=EF\\AB=ED\\BC=DF

we know that

the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Step 1

<u>Find the distance AB</u>

A(0,1)\\B(0,2)

substitute in the formula of the distance

d=\sqrt{(2-1)^{2}+(0-0)^{2}}

d=\sqrt{(1)^{2}+(0)^{2}}

dAB=1\ unit

Step 2

<u>Find the distance BC</u>

B(0,2)\\C(3,2)

substitute in the formula of the distance

d=\sqrt{(2-2)^{2}+(3-0)^{2}}

d=\sqrt{(0)^{2}+(3)^{2}}

dBC=3\ units

Step 3

<u>Find the distance AC</u>

we know that

the triangle ABC is a right triangle

so

Applying the Pythagorean Theorem

AC^{2}=AB^{2} +BC^{2}

substitute the values in the formula

AC^{2}=1^{2} +3^{2}

AC=\sqrt{10}\ units=3.16\ units

round to the nearest tenth

AC=3.2\ units

therefore

EF=3.2\ units

ED=1\ unit

DF=3\ units

<u>the answer is</u>

The length of the hypotenuse is equal to 3.2\ units

Vlada [557]4 years ago
4 0
I think the figure is that of a right triangle.

Its short leg = 2 - 1 = 1 unit     This is the value of y.
Its long leg = 3 - 0 = 3 units    This is the value of x.

Use the Pythagorean theorem to solve for the hypotenuse.

a² + b² = c²
1² + 3² = c²
1 + 9 = c²
10 = c²
√10 = √c²
3.16 = c

The length of the hypotenuse is C.) 3.2   rounded to the nearest tenth.
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Its easy pls help{6x+4y=14}{9x+6y=c}which value of c represents a system with infinitely many solutions?
natka813 [3]

The system of equations 6x+4y=14 and 9x+6y=c are linear equations

The value of c that makes the system have infinitely many solutions is 21

<h3>How to determine the value of c?</h3>

The system of equations are given as:

6x+4y=14

9x+6y=c

Divide through the second equation by 3

3x + 2y = c/3

Multiply through by 2

6x + 4y = 2c/3

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3 years ago
A store sells candy at $.50, $1, $1.50, $2, and $3 per kilogram. You can see that the unit price of candies and the amount of ca
Alecsey [184]

Answer:

Constant of variation = 3

Step-by-step explanation:

Given that a store is selling different candies costing  $.50, $1, $1.50, $2, and $3 per kilogram.

As given

Amount available to buy candies = $ 3

Suppose

Unit price of candies = x

Number of candies bough = y

Constant of variation = k

As we know the unit price of candies and number of candies bought vary inversely. As the unit price would increase the the number of candies bought in available amount ($3) would decrease.

So our formula to calculate formula for constant of variation would be as shown below:

k= xy →(1

Case 1

if we take unit price x to be $0.5, then we can buy 6 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (0.5)(6) = 3

Case 2

if we take unit price x to be $1, then we can buy 3 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1)(3) = 3

Case 3

if we take unit price x to be $1.5, then we can buy 2 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1.5)(2) = 3

Case 4

if we take unit price x to be $2, then we can buy 1.5 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (2)(1.5) = 3

Case 4

if we take unit price x to be $3, then we can buy 1 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (3)(1) = 3

So, our constant of variation is 3.

4 0
4 years ago
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