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3 years ago

Write an equation in slope-intercept form for the line with slope 3/4 and y-intercept -1.

Mathematics

1 answer:

Stels [109]3 years ago

4 0

Answer:

y= $\frac{3}{4}\\$ x-1

Step-by-step explanation:

The slope intercept form is in y=mx+b. Therefore you plug in the following:

- slope = m

- y-intercept = b

Since the problem gives both of these informations you just have to plug it in.

You might be interested in

Apple tarts sell for 3 for$5.00. How much will 8 tarts cost?

MAXImum [283]

Answer:

Step-by-step explanation:

Step one:

given

We are told that 3 apples seels for $5

let us first find the selling price of 1 apple

an apple = 5/3

=$1.6

Required

Step two:

The selling price of 8 apples

if 1 apple sells for $1.6

then 8 apples will sell for

=8*1.6

=$13.30

8 0

3 years ago

Is 20 hundredths equal to 2 thousandths

tester [92]

Hello, you are asking of 20 hundredths are equal to 2 thousandths.

First of all, 1 thousandth = 1/1000 = 0,001

So, 2 thousandths = 2/1000 = 0,002

And 1 hundredth = 1/100 = 0,01

So, 20 hundredths = 20/100 = 0,2

0,2 is ≠ 0,002

So 20 hundredths are not equal to 2 thousandths

8 0

4 years ago

A trust fund worth $25,000 is invested in two different portfolios. This year, one portfolio is expected to earn 5.25% interest

solong [7]

Answer:

$12 000 in Portfolio 1 and $13 000 in Portfolio 2

Step-by-step explanation:

The formula for simple interest is

I = Prt

For each portfolio, t = 1 yr

For Portfolio 1, i = 5.25 % = 0.0525

For Portfolio 2, i = 4 % = 0.04

Let x = amount invested in Portfolio 1. Then

25 000 - x = amount invested in Portfolio 2 and

$\begin{array}{rcr}0.0525x + 0.04(25000- x) & = & 1150\\0.0525x+ 1000 - 0.04x & = & 1150\\0.0125x + 1000 & = & 1150\\0.0125x & = & 150\\x & = & 12000\\\end{array}$

25 000 - x = 25 000 - 12 000 = 13 000

So, $12 000 is invested in Portfolio 1 and $13 000 is invested in Portfolio 2.

Check:

$\begin{array}{rcl}0.0525 \times 12000 + 0.04(25000 - 12000)& = & 1150\\630 + 0.04(13000) & = & 1150\\630 + 520 & = & 1150\\1150 & = & 1150\\\end{array}$