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dlinn [17]
3 years ago
8

II. The results of a recent survey indicate that the average new car costs $23,000, with a standard deviation of $3,500. The pri

ce of cars is normally distributed. a. What is a Z score for a car with a price of $33,000? b. What is a Z score for a car with a price of $30,000?
Mathematics
1 answer:
blsea [12.9K]3 years ago
3 0

Answer:

a) Z = 2.86

b) Z = 2

Step-by-step explanation:

Z-score:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 23000, \sigma = 3500

a. What is a Z score for a car with a price of $33,000?

This is Z when X = 33000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{33000 - 23000}{3500}

Z = 2.86

b. What is a Z score for a car with a price of $30,000?

This is Z when X = 30000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{30000 - 23000}{3500}

Z = 2

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2 years ago
A realtor would like to create a 95% confidence interval for the average price of a house in Franklin County, Ohio. To accomplis
VMariaS [17]

Answer:

320128-1.96\frac{50324}{\sqrt{529}}=315839.52    

320128+1.96\frac{50324}{\sqrt{529}}=324416.48    

So on this case the 95% confidence interval would be given by (315839.52;324416.48)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=320128 represent the sample mean

\mu population mean (variable of interest)

\sigma=50324 represent the population standard deviation

n=529 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

320128-1.96\frac{50324}{\sqrt{529}}=315839.52    

320128+1.96\frac{50324}{\sqrt{529}}=324416.48    

So on this case the 95% confidence interval would be given by (315839.52;324416.48)    

8 0
3 years ago
If the simple interest on $6,000 for 4 years is $1,920, then what is the interest rate?
Vsevolod [243]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
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