The correct answer is C) (5m^50 - 11n^8) (5m^50 + 11n^8)
We can tell this because of the rule regarding factoring the difference of two perfect squares. When we have two squares being multiplied, we can use the following rule.
a^2 - b^2 = (a - b)(a + b)
In this case, or first term is 25m^100. So we can solve that by setting it equal to a^2.
a^2 = 25m^100 -----> take the square root of both sides
a = 5m^50
Then we can do the same for the b term.
b^2 = 121n^16 ----->take the square root of both sides
b = 11n^8
Now we can use both in the equation already given
(a - b)(a + b)
(5m^50 - 11n^16)(5m^50 + 11n^16)
The answer is 6m - 6 = 8m + 4
Hope this helps please give brainless!!!
Answer:
1/21
Step-by-step explanation:
The baker makes 84 loaves of bread,
Out of the 84 bread, 4 of them got burn.
Fraction that the loaves does the burn will be expressed in 4/84 = 1/21.
Answer:
The value is 
Step-by-step explanation:
From the question we are told that
The probability of passing the test is 
The sample size is n = 10
Generally the distribution of the comprehensive testing of equipment follows a binomial distribution
i.e

and the probability distribution function for binomial distribution is

Here C stands for combination hence we are going to be making use of the combination function in our calculators
Generally the probability that at least 9 pass the test is mathematically represented as

=> ![P(X \ge 9) = [^{10}C_9 * (0.95)^9 * (1- 0.95)^{10-9}] + [^{10}C_{10} * (0.95)^{10} * (1- 0.95)^{10-10}]](https://tex.z-dn.net/?f=P%28X%20%5Cge%209%29%20%3D%20%20%5B%5E%7B10%7DC_9%20%2A%20%20%280.95%29%5E9%20%2A%20%20%281-%200.95%29%5E%7B10-9%7D%5D%20%2B%20%5B%5E%7B10%7DC_%7B10%7D%20%2A%20%20%280.95%29%5E%7B10%7D%20%2A%20%20%281-%200.95%29%5E%7B10-10%7D%5D)
=> ![P(X \ge 9) = [0.3151] + [0.5987]](https://tex.z-dn.net/?f=P%28X%20%5Cge%209%29%20%3D%20%20%5B0.3151%5D%20%2B%20%5B0.5987%5D%20)
=> 