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4 years ago

Please help me im stuck

Mathematics

1 answer:

MArishka [77]4 years ago

5 0

Depending on what you need help with I am here at any time :/

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60? idk really srsly lalalalalallala

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3 years ago

i need to know what the area of a triangle is with a base of 27 ft and a height of 12 ft? I took 12x27=324/2 = 162 and I don't h

Mamont248 [21]

Based on what I learned in school, your answer should be correct. I double checked the calculations:)

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4 years ago

Three pizzas are share equally among 12 people. What fraction will each person get

victus00 [196]

Answer:

1/4

Step-by-step explanation:

if you take the fraction 3/12 and divide it by 3 on both sides, you get the remaining fraction 1/4

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3 years ago

Read 2 more answers

If Y=2x+5 and Y=1/2x-1 what is the solution?

kkurt [141]

2x + 5 = 0.5x - 1

(Multiplying by 2 cause I hate fractions/decimals)

4x + 10 = x - 2

3x + 10 = -2

3x = -12

x = -4

Y = 2x + 5

Y = 2(-4) + 5

Y = -8 + 5

Y = -3

Y = 0.5x - 1

Y = 0.5(-4) - 1

Y = -2 - 1

Y = -3

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8 0

4 years ago

A circle has a radius of 9 inches. The Radius is multiplied by 2/3 to form a second circle. How is the ratio of the areas relate

liraira [26]

Answer:

$\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81}{36} = (\frac{r_{1} }{r_{2}}) ^{2}$

The above expression shows that ratios of the areas of the circles are equal to the square of the ratio of their radii.

Step-by-step explanation:

Radius of first circle $(r_{1})$ = 9 inches

Area of first circle = $\pi r_{1} ^{2}$

Area of first circle = 9 × 9 × π = 81 π

Now, since the radius is multiplied by 2/3 for from a new circle.

∴ Radius of the second circle = $9 \times \frac{2}{3} = 6\ inches$

Area of second circle = $\pi r_{2} ^{2}$

Area of second circle = 6 × 6 × π = 36 π

Now,

$\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81\pi }{36\pi }$

$\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81}{36} = (\frac{9}{6}) ^{2} = (\frac{r_{1} }{r_{2}}) ^{2}$

∵ $(r_{1})$ = 9 inches and $(r_{2})$ = 6 inches

The above expression shows that ratios of the areas of the circles are equal to the square of the ratio of their radii. i.e., $\frac {radius\ of\ first\ circle)^{2} }{(radius\ of\ second\ circle)^{2} } = \frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)}$

8 0

3 years ago