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grigory [225]
3 years ago
13

ALGEBRA 1 URGENT HELP!!

Mathematics
1 answer:
larisa [96]3 years ago
5 0
40x+ 5y=8
You have to clear the fraction on the x value
You might be interested in
Suppose that 2000 is invented at a rate of 3.5%, compounded semiannually. Assuming that no withdrawals are made, find the total
Vinvika [58]

Answer:

$2,297.76

Step-by-step explanation:

Present value: P = 2000

Future value: F

Annual interest rate: r = 3.5% = 0.035

Time: t = 4 years

Number of compounding periods per year: n = 2

F = P(1 + \dfrac{r}{n})^{nt}

F = 2000(1 + \dfrac{0.035}{2})^{2 \times 4}

F = 2000(1 + 0.0175)^{8}

F = 2000(1.0175)^{8}

F = 2000(1.148881783)

F = 2297.76

Answer: $2,297.76

6 0
3 years ago
12. If DH = HE, MBG = (9x – 20) and <br> MGC = (5x + 28), find mAB.
svetoff [14.1K]

Answer:

176degrees

Step-by-step explanation:

Find the diagram attached. From the diagram;

arcGC  = = arc BG

5x + 28 = 9x - 20

5x - 9x = -20  28

-4x = -48

x = -48/-4

x = 12

Get <AB

Since <AB = <BC

<BC = arcGC +arc BG

<AB = arcGC+ arc BG

<AB = 5x + 28 + 9x - 20

<AB = 14x + 8

<AB = 14(12) + 8

<AB = 168 + 8

<AB = 176degrees

Hence the arc AB is 176degrees

5 0
3 years ago
Will any ramp with a slope ratio of 1:12 have an angle of 4.8 degrees?
lawyer [7]

Answer: yes

Step-by-step explanation:

7 0
2 years ago
Help please?!?!?!?!?!?!?
nadezda [96]

Answer:

Choice D is  correct answer.

Step-by-step explanation:

We have given two function.

f(x) =2ˣ+5x  and g(x)  = 3x-5

We have to find the addition of given two function.

(f+g)(x) =  ?

The formula to find the addition, we have

(f+g)(x) = f(x) + g(x)

Putting given values in above formula, we have

(f+g)(x) =   (2ˣ+5x)+(3x-5)

(f+g)(x) =   2ˣ+5x+3x-5

Adding like terms, we have

(f+g)(x) =   2ˣ+8x-5 which is the answer.

6 0
3 years ago
Let P(x,y) be a propositional function if ꓯyꓱxP(x,y) is true does it necessarily follow that ꓱxꓯyP(x,y) is true? Justify your an
andrew11 [14]

Answer:

It is NOT TRUE

Step-by-step explanation:

ꓯyꓱxP(x,y)  

means that for each value of  y there exist x such that P(x,y) is true

whereas

ꓱxꓯyP(x,y)

means that there exists x such that for each value y, P(x,y) is true.

In the second case, the same x must work for every element y.

Counter-example

Consider  

P(x,y) the following proposition

x-y = 0, for x, y integers.

Given an integer y, there is another integer x (namely, x=-y) such that

x-y = 0

so, ꓯyꓱxP(x,y) is TRUE

If ꓱxꓯyP(x,y) were TRUE, then would exist a single unique value of x such that P(x,y) is TRUE for every integer y.

Then P(x,1) and P(x,2) would be both TRUE and

x-1 = 0

x-2 = 0

and we conclude 1=2, which is a contradiction.

So  ꓱxꓯyP(x,y) is NOT TRUE (FALSE)

5 0
3 years ago
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