The shape of the room is not a square.
Pythagorean Theorem: 17^2+17^2= 578, square root 578 and you'll get 24.04.
The length of the diagonal of the floor of the room in the plan should have been 24.04 in order to be a square.
Answer:
The answer is 61.
Step-by-step explanation:
Let, the numbers are: x, (x+2), (x+4)
Now, x+x+2+x+4 = 183
3x + 6 = 183
3x = 177
x = 59
So, second number would be: (x+2) = (59+2) = 61
Step-by-step explanation:
C=2×pi×r
8.61=2pi*×r
8.61÷2pi=13.52 radius
A=pi×r^2
pi×13.52^2=574.25 area
12 I got it form Socratic
![\bf \sum\limits_{n=2}^{10}~-2n-3](https://tex.z-dn.net/?f=%5Cbf%20%5Csum%5Climits_%7Bn%3D2%7D%5E%7B10%7D~-2n-3)
so, let's first change the bounds from 1 to 9, so we'll be dropping the indices by 1, in order to do the variable "n".
however, let's use a variable hmmm say "k", where "k" is the value of "n" beginning at 1, thus
k = n - 1.
however, if k = n - 1, then
k + 1 = n. So let's use those fellows then,