Ask question

Ask question

All categories

Ksenya-84 [330]

3 years ago

15

Can someone help with this

1 answer:

gtnhenbr [62]3 years ago

4 0

Answer:

No, you should your best. Belivie in your self that you can do it.

Step-by-step explanation:

You might be interested in

What is 21 divided by 50

Trava [24]

Answer:

o.42

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

Please help me !!!!!!!

umka21 [38]

$\frac{2}{3}y+15=9 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Given} \\\\ \frac{2}{3}y+15-15=9-15 \ \ \ \ \ \ \ \ \text{Subtraction property} \\ \\ \frac{2}{3}y=-6 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Simplification} \\ \\ \frac{2}{3}y \cdot \frac{3}{2} =-6\cdot \frac{3}{2} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Multiplication property} \\\\ y=-9 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Simplification}$

8 0

3 years ago

HELLLP PLSsssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss

valentinak56 [21]

Answer: A and D are your answers

4 0

3 years ago

Read 2 more answers

Jeremy completes eight extra credit problems on the first day and then for problems each day until the work is complete their 28

Novay_Z [31]

I THINK there is a typo. Instead of "for problems each day", i think it's "four problems each day."

Anyway, we need to find how many days it takes Jeremy to complete the paper.

If he completes 8 problems on the first day and 4 on the rest of the days, after the first day he'll have 28 - 8 = 20 more problems.

And since he does 4 every day with 20 problems: 20 / 4 = 5 days.

7 0

4 years ago

Consider the quadratic function f(x)=−x^2+x+30

yaroslaw [1]

Answer:

The smallest xx-intercept is $x = -5$

The largest xx-intercept is $x = 6$

The yy-intercept is $y = 30$ .

Step-by-step explanation:

Given a quadratic function in the following format:

$f(x) = ax^{2} + bx + c = 0, a \neq 0$

The x-values of the x-intercepts are $x_{1}, x_{2}$ , given by the following formulas.

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

We have that:

$f(x) = -x^{2} + x + 30$

This is not in the format above. I will multiply by (-1), so we have:

$f(x) = x^{2} - x - 30$

So, $a = 1, b = -1, c = -30$

$\bigtriangleup = b^{2} - 4ac = (-1)^{2} - 4*(1)*(-30) = 1 + 120 = 121$

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a} = \frac{-(-1) + \sqrt{121}}{2(1)} = \frac{12}{2} = 6$

$x_{2} = \frac{-b + \sqrt{\bigtriangleup}}{2*a} = \frac{-(-1) - \sqrt{121}}{2(1)} = \frac{-10}{2} = -5$

This means that

The smallest xx-intercept is $x = -5$

The largest xx-intercept is $x = 6$

The y-intercept is the value of f(x) when x = 0. So

$f(x)=−x^{2}+x+30$

$f(0) = 30$

The yy-intercept is $y = 30$ .

5 0

3 years ago