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fenix001 [56]
2 years ago
5

A quadrilateral has vertices E(–4, 2), F(4, 7), G(8, 1), and H(0, –4). Which statements are true? Check all that apply.

Mathematics
1 answer:
lys-0071 [83]2 years ago
8 0

Answer:

D) Quadrilateral EFGH is a parallelogram because both pairs of opposite sides are parallel.

B) The slopes of EF and GH are both 5/8

Step-by-step explanation:

The following inference can be made about each answer choices:

For option A

A) The slope of EH is 3/2 and not -8/5

For EH, slope = (2--4)/(0--4) = 6/4 =3/2

For option B

B) The slopes of EF and GH are both 5/8

slope of a graph can be determined by change in y axis/ change in x axis

For EF, slope = (7-2)/(4--4) = 5/8

for GH, slope =  (1--4)/(8-0) = 5/8

For option C

C) FG is perpendicular to GH, its can't be determined since it is concluded that the quadrilateral is a parallelogram, therefore this option is wrong.

For option D

D) Quadrilateral EFGH is a parallelogram because both pairs of opposite sides are parallel.

Slope of a graph can be determined by rise divided by run change in y axis/ change in x axis

For EF, slope = (7-2)/(4--4) = 5/8

for GH, slope =  (1--4)/(8-0) = 5/8

For EH, slope = (2--4)/(0--4) = 6/4 =3/2

for FG, slope =  (7-1)/(8-4) = 6/4 =3/2

EF and GH give the same slope, likewise EH and FG and they are opposite to each other, this make them parallel. Therefore, EFGH is a parallelogram.

Refer Below link for further details:

brainly.com/question/18006680

#SPJ10

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1 Point
I am Lyosha [343]

Option C

The ratio for the volumes of two similar cylinders is 8 : 27

<h3><u>Solution:</u></h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

\text { Volume of a cylinder }=\pi r^{2} h

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e  

\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}

<em><u>Ratio for the volumes of two cylinders</u></em>

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}

Cancelling the common terms, we get

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)

Substituting we get,

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}

Hence, the ratio of volume of two cylinders is 8 : 27

7 0
3 years ago
You are given g(x)=4x^2 + 2x and
Strike441 [17]

Answer:

324

Step-by-step explanation:

Given:

g(x)=4x^2+2x\\ \\f(x)=\int\limits^x_0 {g(t)} \, dt

Find:

f(6)

First, find f(x):

f(x)\\ \\=\int\limits^x_0 {g(t)} \, dt\\ \\=\int\limits^x_0 {(4t^2+2t)} \, dt\\ \\=\left(4\cdot \dfrac{t^3}{3}+2\cdot \dfrac{t^2}{2}\right)\big|\limits^x_0\\ \\=\left(\dfrac{4t^3}{3}+t^2\right)\big|\limits^x_0\\ \\= \left(\dfrac{4x^3}{3}+x^2\right)-\left(\dfrac{4\cdot 0^3}{3}+0^2\right)\\ \\=\dfrac{4x^3}{3}+x^2

Now,

f(6)\\ \\=\dfrac{4\cdot 6^3}{3}+6^2\\ \\=288+36\\ \\=324

4 0
3 years ago
2 ( 3 x 4) - 10 + 14/2 = 21<br><br> true or false
larisa86 [58]

Answer:

true

Step-by-step explanation:

7 0
3 years ago
Help Please! I dont get it
KIM [24]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ The formula to calculate the circumference is \pi d

d is the diameter (double the radius)

Substitute the values in:

Circumference = (3.14)(3 x 2)

Circumference = 18.84

It would be option D. 18.84 m

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

8 0
3 years ago
Read 2 more answers
Quinzel earns $1,254 each month. His total deductions are 20% of his pay. How much is deducted from his pay each month? A. $62.7
Blababa [14]
The answer is C. 250.80

change the percent to a decimal (0.20) and multiply 1,254x0.20=250.80
6 0
3 years ago
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