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Dovator [93]
3 years ago
6

Polygon ABCDE is the first in a pattern for a high school art project. The polygon is transformed so that the image of A' is at

(-2, 2) and the image of Dis at (-3,0). Which transformation can be used to show that ABCDE
and its image are congruent?

Mathematics
1 answer:
Bond [772]3 years ago
3 0

Answer:

Translation

Step-by-step explanation:

To keep a shape congruent or the same then you can Translate or to slide the shape not to change any sides.

You might be interested in
What is 4/6/10 plus 6/10 fractions
Paul [167]

Answer:

5 and 1/5

Step-by-step explanation:

it is written like this 4 and 6/10 + 6/10

so its 4 and (6+6) 12/10


12-10= 2 = 1 and 1/5

4 +1= 5

so now you have 5 and 1/5


YaYYYY hun xD

7 0
3 years ago
Find the area of the trapezoid.
goldenfox [79]

Answer:

<h3>105m²</h3>

Step-by-step explanation:

AREA=

\frac{(a + b)}{2}  \times h

\frac{15 + 6}{2}  \times 10

=105m²

6 0
3 years ago
Uninhibited growth can be modeled by exponential functions other than​ A(t) ​=Upper A 0 e Superscript kt. For ​ example, if an i
laila [671]

The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than A(t)=A_{0}e^{kt}. for example, if an initial population P₀ requires n units of time to triple, then the function P(t)=P_{0}(3)^{\frac{t}{n} } models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form P(t)=P_{0}(3)^{\frac{t}{n} } that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form A(t)=A_{0}e^{kt}.

Answer: a) P(t)=50(3)^{\frac{t}{30} }

              b) P(t) = 280 insects

              c) t = 74 days

             d) A(t)=50e^{0.037t}

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

P(t)=50(3)^{\frac{t}{30} }

b) In t = 47 days:

P(t)=50(3)^{\frac{t}{30} }

P(47)=50(3)^{\frac{47}{30} }

P(47)=50(3)^{1.567}

P(47) = 280

In 47 days, population of insects will be 280

c) P(t) = 750

750=50(3)^{\frac{t}{30} }

\frac{750}{50}=(3)^{\frac{t}{30} }

(3)^{\frac{t}{n} }=15

Using the property <u>Power</u> <u>Rule</u> of logarithm:

log(3)^{\frac{t}{30} }=log15

\frac{t}{30}log(3)=log15

t=\frac{log15}{log3} .30

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

A(t) = 3A₀ and t = 30

A(t)=A_{0}e^{kt}

3A_{0}=A_{0}e^{30k}

3=e^{30k}

Use Power Rule again:

ln3=ln(e^{30k})

ln3=30k

k=\frac{ln3}{30}

k = 0.037

Equation for exponential growth will be:

A(t)=50e^{0.037t}

3 0
3 years ago
⦁ What is the sum of the measures of the exterior angles in a heptagon? Explain.
Ratling [72]
<span>Your answer would be 360 the sum of the exterior angles of any convex polygon is 360 degrees</span>
6 0
3 years ago
It’s really confusing, I could really use some guidance.
Dafna1 [17]

Answer:

See below.

Step-by-step explanation:

Let x equal each of the values on the table, and find the value of the function for that value of x.

f(x) = 5x - 5

x = -4

f(-4) = 5(-4) - 5

f(-4) = -20 - 5

f(-4) = -25

x = 0

f(0) = 5(0) - 5

f(0) = 0 - 5

f(0) = -5

x = 1

f(1) = 5(1) - 5

f(1) = 5 - 5

f(1) = 0

x = 3

f(3) = 5(3) - 5

f(3) = 15 - 5

f(3) = 10

x = 5

f(5) = 5(5) - 5

f(5) = 25 - 5

f(5) = 20

x          f(x)

-4        -25

0          5

1           0

3          10

5          20

5 0
3 years ago
Read 2 more answers
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