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riadik2000 [5.3K]
3 years ago
9

A softball pitcher has 0.626 probability of throwing a strike for each pitch if the softball pitcher throws 30 pitches what is t

he probability that no more than 16 of them are strikes?
Mathematics
1 answer:
coldgirl [10]3 years ago
6 0
The probability that pitcher will throw no more than 16 strikes is 0.1938.
You might be interested in
If he = 7x -27 find the value of x
Amiraneli [1.4K]

\\ \sf\longmapsto 7x-27=1

\\ \sf\longmapsto 7x=1+27

\\ \sf\longmapsto 7x=28

\\ \sf\longmapsto x=\dfrac{28}{7}

\\ \sf\longmapsto x=4

5 0
3 years ago
What is the possibility that a red or green marble will be selected from a bag containing 9 red marbles, 6 blue marbles , 7 gree
marusya05 [52]

Answer:

16/33

Step-by-step explanation:

We have a bag of :

9 red marbles

6 blue marbles

7 green marbles

11 yellow marbles

Total number of marbles = 33 marbles.

The possibility that a red or green marble will be selected from a bag

P( Red or Green) = P(Red) + P(Green)

In the question we are not told if it is with replacement or without. We do both

With replacement

P( R or G) = P(Red) + P(Green)

P(Red)= 9/33

P(Green) = 7/33

= 9/33 + 7/33

= 16/33

Therefore, the possibility that a red or green marble will be selected from a bag is 16/33

8 0
3 years ago
The sum of two numbers is 83 if one of the number is 7 more than the other find the two numbers?​
viva [34]

Answer:

48.5 and 34.5

Step-by-step explanation:

83 divided by 2 and then subtract 7

3 0
3 years ago
Read 2 more answers
A rectangular garden must have a perimeter of 150 feet and an area of at least 1200 square feet. Describe the possible lengths o
kipiarov [429]

Answer: 51.86 and 23.14

Step-by-step explanation:

The rectangular garden must have a perimeter of 150 feet

Perimeter of rectangular garden =

2l + 2w=150 -----------1

The rectangular garden must have a perimeter of 150 feet and an area of at least 1200 square feet.

Area of rectangular garden =

l×w= 1200 feet^2 -----------2

From equation 2, l=1200/w

Put l=1200/w in equation 1

2× 1200/w + 2w = 150

(2400/w) +2w = 150

(2400+2w^2)/w =150

2400+2w^2= 150w

2w^2- 150w+2400=0

Using the general formula

w = [-b+-√(b^2-4ac)]/2a

a = 2, b =-150, c=2400

w =[--150+/-√(-150^2-4×2×2400)]/2×2

=[150+/-√(22500-19200)]/4

=[150+/-√3300)]/4

=(150+57.45)/4 or (150-57.45)/4

w= 207.45/4 or 92.55/4

w= 51.86 or w= 23.14

l = 1200/51.86 or l= 1200/23.14

l = 23.14. or l= 51.86

For an area of at least 1200ft^2

The dimensions are 51.86 and 23.14

4 0
3 years ago
Find x inscribed angles
mina [271]
The easiest variable you can solve for first is "z". Knowing that opposite angles of a quadrilateral inscribed in a circle are supplementary, subtract 93 from 180 to get z.
Z should equal 87.
The next variable we can solve for is "x". We know that inscribed angles are half the measure of their intercepting arc, so we know 93 is half of (112 + x). The equation would look like this:

93= (112 + x)/2
Multiply both sides by 2
186 = 112 + x
Subtract 112 from both sides
74 = x

Now we can apply the same method we used to find "x" to find y. Set up an equation like this:
80 = (y + x)/2
Substitute the value of x in
80 = (y + 74)/2
Multiply both sides by 2
160 = y + 74
Subtract 74 from both sides
86 = y

Hope this helps!
5 0
3 years ago
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