3 years ago

What is the sum of the given polynomials in standard from? (x^2 -3x) + (-2x^2+5x-3)

1 answer:

8 0

The pic will help you

Good luck:))

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OleMash [197]

480. And I don't understand the bottom part

4 0

3 years ago

Hunter-Best [27]

If im sure it should be c

7 0

3 years ago

Radda [10]

10/2= 5 so 5: 5 x 5 so the length is 25. 6/3 = 2 so 2: 2 x 5 = 10.
Area is length times width. 25 x 10= 250

3 0

4 years ago

charle [14.2K]

Answer: t = - 5 ∈ $I_{1}$ = ( -∞ , -4 )

Step-by-step explanation:

The standard form of O.D.E is written as :

$y^{1}$ + $p(t) = g(t)$

Equation given :

$(16-t^{2} )y^{1}$ + $9ty$ = $5t^{2}$ , $y(-5) = 1$

The first thing to do is to write the O.D.E in standard form , that is we will divide through by $16 - t^{2}$ , so we have

$y^{1} + \frac{9ty}{16-t^{2}}=\frac{5t^{2}}{16-t^{2}}$

With this , we can see that $p(t)$ and $g(t)$ are both continuous in the same domain. Therefore , the intervals are :

$I_{1}$ = ( -∞ , -4 )

$I_{2}$ = ( - 4 , 4 )

$I_{3}$ = ( 4 , -∞ )

recall that y(−5) = 1 , then t = -5

This means that :

t = - 5 ∈ $I_{1}$ = ( -∞ , -4 )

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4 years ago

Sauron [17]

21 not sure but you can do it

6 0

3 years ago