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Contact [7]
3 years ago
6

One brother says of his younger brother: “Two years ago, I was three times as old as my brother was. In three years’ time, I wil

l be twice as old as my brother.” How old are they each now?
Mathematics
2 answers:
BARSIC [14]3 years ago
8 0

Answer:

One brother says of his younger brother: “Two years ago, I was three times as old as my brother was. In three years’ time, I will be twice as old as my brother.” How old are they each now?

Step-by-step explanation:

Let us suppose two years ago my brother's age was x years

Then, my age was 3x

Three years from now, my brother's age will be (x +2+3) = (x+5) years

And my age will be (3x+2+3) = (3x+5) years

But it is given that i will be twice as old as my brother.

So, 2(x+5)= (3x+5)

or, x= 5 years

So my brother's present age is 5+2= 7 years

And my age is 5*3+2= 17 years

marin [14]3 years ago
6 0
He would have been 17 years of age.
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Answer:

<u></u>

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Explanation:

The complete question is:

<em>Between the time iko woke up and lunchtime, the temperature rose by 11º. Then by the time he went to bed, the temperature dropped by 14º.</em>

<em />

<em>Write an addition expression for the temperature relative to when iko woke up. </em>

<em />

<h2>Solution</h2>

It is said that between the time Iko woke up and lunchtime, the temperature rose by 11 degrees. A rise means the temperature increased and you must add 11º.

Then, relative to when Iko woke up the temperature is:

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Then, by the time Iko went to bed, the temperature dropped by 14º. A drop means that the change is negative. This means that you must add a negative number, and the additive expression is:

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If you want the overall change in temperature you do the operation:

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But the answer to this question is the additive expression:

  • 11 + ( - 14) ← answer
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