This is similar to the other question you posted. Follow the same steps as before.
First find g(41).
g(41) = sqrt{x - 5}
g(41) = sqrt{41 - 5}
g(41) = sqrt{36}
g(41) = 6
We now find f(6).
f(6) = -7(6) + 1
f(6) = -42 + 1
f(6) = -41
Answer:
(fºg)(41) = -41
Did you follow?
Answer:
36
Step-by-step explanation:
Compare what you have to the square ...
(a +b)^2 = a^2 +2ab +b^2
Your "a" is √(25x^2) = 5x
Your "2ab" is -60x. Since you know "a", you can find "b".
2ab = -60x
2(5x)b = -60x . . . . . . . substitute for "a"
b = -60x/(10x) = -6
Then the missing term is b^2 = (-6)^2 = 36.
Your trinomial is ...
25x^2 -60x +<u>36</u>
Answer:
He said points
Step-by-step explanation:
I can get points for nothing
The answers to the questions
X = 66°
The area folded over is a right triangle, and its void is a right triangle as well. We have one angle marked 33° and a right angle in the bottom left. This leaves us 180-(33+90) = 180-123 = 57°.
The folded over triangle has the same angle measurements.
We have two angles to the left of x, which form a straight angle with x. Straight angles have a sum of 180°. The angles that form the straight angle with x both have a measure of 57°. This gives us:
180-(57+57) = 180-114 = 66°
