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Sergio039 [100]
3 years ago
9

Can you please help me with this side of these problems.

Mathematics
1 answer:
Vlad [161]3 years ago
5 0

Answer:

6: Reason 2 - substitution, Statement 4 - PR congruent to PR, Reason 4 - reflexive property, Reason 5 - AAS

8: Rotation

Step-by-step explanation:

6: Since both of the given angles equal 90°, you can <em>substitute</em> Angle RPT in to make Angle PRQ congruent to Angle RPT. Then, since both triangles share Line PR, <em>PR would be congruent to PR</em> by the <em>reflexive property</em>. And since you know that Angle Q is congruent to Angle T, you can see that Triangle QRP is congruent to Triangle TPR by the <em>AAS theorem</em>.

8: Since the 1st triangle is pointing to the right and the 2nd triangle is pointing downward, this would be a rotation of 90° clockwise (or 90° counterclockwise if the 1st triangle is the one pointing downward)

I don't have 7, sorry.

Also (if you haven't noticed it already), there's a typo in the 1st statement of the proof. Just thought I'd let you know ;)

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4 years ago
Taimiah was running down the street with her dog Slugger. She ran 8.56 miles and Slugger ran 4.34 miles. Add these decimals.
Gnoma [55]
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3 years ago
AC=<br> Help me please!! Thanks so much
katovenus [111]

Answer:

AC = 6√3 in

Step-by-step explanation:

<h3>Finding the length of the chord:</h3>

Join OC. Now ΔAOC is an isosceles triangle as OA = OC =radius.

 ∠A = ∠C = 30.

 ∠A + ∠C +  ∠AOC = 180 {angle sum property of traingle}

 30 + 30 + ∠AOC  = 180°

                 ∠AOC = 180 -60

                 ∠AOC = Ф = 120°

Find the length of radius using the bellow formula.

         \sf \boxed{\bf Arc \ length = \dfrac{\theta}{180}\pi r}

            Ф = 120°

                Arc length = 4π

            \sf  4\pi =\dfrac{120}{180}*\pi *r\\\\      r =\dfrac{4\pi * 180}{120*\pi }\\\\    r = 6 \ in

\sf \boxed{\bf chord \ length = 2rSin \ \dfrac{\theta}{2}}

                         \sf b = 2*6*Sin \ \dfrac{120}{2}\\\\  b = 2 *6 * Sin \ 60^\circ\\\\  b = 2 * 6 * \dfrac{\sqrt{3}}{2}\\\\ \b = 6\sqrt{3}

\sf \boxed{\bf AC = 6\sqrt{3} \ in}

5 0
2 years ago
Cindy was asked by her teacher to subtract 33 from a certain number and then divide the result by 99. ​Instead, she subtracted 9
Ainat [17]
You should get 1044.3 repeated
6 0
3 years ago
Alonzo is $120 in debt. He makes S15 per hour. He wants to have at least $75 left over after he has paid off his debt. What's th
iragen [17]

Given that,

Alonzo is $120 in debt. He makes $15 per hour. He wants to have at least $75 left over after he has paid off his debt.

To find,

The inequality and the solution.

Solution,

Let he make $x per hour. Here, $120 is fixed. $15 is added per hour.

ATQ,

120 + 15x\ge 75

For atleast, we use \ge.

Subtract 120 from both sides.

120 + 15x-120\ge 75-120\\\\15x\ge -45\\\\x\ge -3

So, the required answer is greater than -3.

6 0
3 years ago
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