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inysia [295]
2 years ago
11

Bruce collects the data on four electric circuits listed in the table. a 3 column table with 4 rows. the first column is labeled

circuit with entries w, x, y, z. the second column is labeled voltage in volts with entries 18, 24, 34, 12. the last column is labeled resistance in ohms with entries 38, 34, 70, 18. bruce must report any circuits that deliver more than 4.0 c of charge in 8.0 s. which lists every circuit that bruce must include in his report? x and z x and y w and y w and z
Mathematics
1 answer:
cricket20 [7]2 years ago
5 0

The Bruce must include X and Z in his report.

We have given  the data on four electric circuits listed in the table

For w :

Voltage, V=18\ V

resistance, R=38\ \Omega

<h3>What is the formula for ohm's low?</h3>

The formula of Ohm's low is V=IR

I=\dfrac{V}{R}

I=\dfrac{18\ V}{38\ \Omega}

I=0.47

q=0.47\times8

So charge,q=It

q=3.76\ C

For x :

Voltage, V=24\ V

resistance, R=34\ \Omega

so, V=IR...(Ohm's low)

I=\dfrac{V}{R}

I=\dfrac{24\ V}{34\ \Omega}

I=0.705

q=0.705\times8

So charge,q=It

q=5.64\ C

For y :

Voltage, V=34\ V

resistance, R=70\ \Omega

so, V=IR.......(Ohm's low)

I=\dfrac{V}{R}

I=\dfrac{34\ V}{70\ \Omega}

I=0.485

q=0.485\times8

So charge,q=It

q=3.88\ C

For z :

Voltage, V=12\ V

resistance, R=18\ \Omega

so, V=IR......(Ohm's low)

I=\dfrac{V}{R}

I=\dfrac{12\ V}{18\ \Omega}

I=0.66

q=0.66\times8

So charge,q=It

q=5.28\ C

Therefore, the circuits X and Z deliver 5.64 C and 5.28 C of charge.

Hence, Bruce must include X and Z in his report.

To learn more about the electric circuit visit:

brainly.com/question/2969220

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omeli [17]

Answer:

<h3>25m</h3>

Step-by-step explanation:

Perimeter of the rectangular pasture P = 2(L+W)

Area A = LW

L is the length

W is the width

Given

Perimeter = 110m

Area = 750m

If the length of the pasture is 40m longer than the width, then L = W+40

110 = 2L+2w

55 = L+W .....1

750 = LW.....2

Solving simultaneously

from 1; L = 55-W

substitute into 2;

750 = (55-W)W

750 = 55W-W²

-W²+55W -750 = 0

W²-55W+750 = 0

(W²-25W)-(30W+750) = 0

W(W-25)-30(W-25) = 0

(W-25)(W-30) = 0

W-25 = 0 and W-30 = 0

w = 25m and 30m

Since L = 55-W

L = 55-25 = 30m and;

L = 55-30 = 25m

Since we are told that length id longer than the width then, the width we are going to use is 25m

7 0
3 years ago
Can someone show me the steps to solving this <br> (Rationalizing Denominator)
Crazy boy [7]

Answer:

\huge  \purple {\frac{2 \sqrt[3]{6} +  \sqrt[3]{18} }{  6}  }

Step-by-step Explanation:

\huge \frac{2 +  \sqrt[3]{3} }{ \sqrt[3]{6} }  \\  \\  =  \huge \frac{(2 +  \sqrt[3]{3} )}{ \sqrt[3]{6} }  \times  \frac{ \sqrt[3]{6}  \times  \sqrt[3]{6} }{\sqrt[3]{6}  \times  \sqrt[3]{6}}  \\  \\ =  \huge \frac{(2 +  \sqrt[3]{3} )}{ \sqrt[3]{6} }  \times  \frac{ \sqrt[3]{6 ^{2} }  }{\sqrt[3]{6^{2}}  } \\  \\ =  \huge \frac{(2 +  \sqrt[3]{3} )\sqrt[3]{6} }{ \sqrt[3]{6} \times \sqrt[3]{6 ^{2} }}  \\  \\ =  \huge \frac{(2 \sqrt[3]{6} +  \sqrt[3]{3} \sqrt[3]{6} )}{  \sqrt[3]{6 ^{3} }}  \\  \\ =  \huge  \orange{\frac{2 \sqrt[3]{6} +  \sqrt[3]{18} }{  6}  }

6 0
3 years ago
Find the domain of the graphed function.
lesya692 [45]
{X| -4 < x < 2, X € R}

Both < signs should be greater than OR EQUAL signs, I just couldn’t find that symbol, sorry.
5 0
3 years ago
See image attached below keeeeeeeeeeeeeeeeeeeed
emmasim [6.3K]

Answer:

.13%

68.26%

2.28%

47.72%

49.87%

34.13%

Step-by-step explanation:

1.) standardize by subtracting the mean and dividng by the standard deviation

(625-1000)/125= -3

go to a ztable to get .0013 or (1-.9987)

this is equal to .13%

2.)

875<x<1125

standardize both seperately and subtract them

(875-1000)/125= -1  whose probability is .1587 (or 1-.8413)

(1125-1000)/125= 1  whose probability is .8413

.8413-.1587= 68.26%

3.)

Find the probability that someone paid less than 1250 and take its compliment

(1250-1000)/125= 2 which has a probability of .9772

take its compliment (1-.9772)= .0228= 2.28%

4.)

Same process as question 2

(750-1000)/125= -2 which has a probability of (1-.9772) = .0228

(1000-1000)/125= 0 which has a probability of .5

.5-.0228= .4772= 47.72%

5.) same deal as the previous question

(625-1000)/125= -3 which has a probability of (1-.9987)= .0013

(1000-1000)/125= 0 which has a probability of .5

.5-.0013= .4987= 49.87%

6.)same deal the previous question

(875-1000)/125= -1 which has a probability of (1-.8413)=.1587

(1000-1000)/125= 0 which has a probability of .5

.5-.1587= .3413= 34.13%

4 0
3 years ago
Jessica's Furniture Store buys a couch at a wholesale price of \$113.00$113.00dollar sign, 113, point, 00.
andrew-mc [135]

Answer:

$50.85

Step by step explanation:

We have been given that Jessica's Furniture Store buys a couch at a wholesale price of $113.00 and the markup rate at Jessica's Furniture Store is 45%.

We can find mark-up for the couch by finding 45% of 113.  

\text{Mark-up}=113\times \frac{45}{100}

\text{Mark-up}=113\times 0.45

\text{Mark-up}=50.85

Therefore, mark-up for the couch will be $50.85.


4 0
3 years ago
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