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2 years ago

Can you please help me? Graph the following equations on the coordinate plane.

Mathematics

2 answers:

rosijanka [135]2 years ago

5 0

Answer:

this is the graph for y= -3x+8

Step-by-step explanation:

katen-ka-za [31]2 years ago

5 0

Y=-3x+8 would be you answer for this one

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lubasha [3.4K]

What homework do you need help with

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3 years ago

15 increased by 40%, I have no idea what that means

elena-s [515]

It’s 21 it technically just means your increasing the 15 by 50 percent

8 0

2 years ago

Please help? I’m super lost...

babunello [35]

Answer:

Step-by-step explanation:

In all of these problems, the key is to remember that you can undo a trig function by taking the inverse of that function. Watch and see.

a. $sin2\theta =-\frac{\sqrt{3} }{2}$

Take the inverse sin of both sides. When you do that, you are left with just 2theta on the left. That's why you do this.

$sin^{-1}(sin2\theta)=sin^{-1}(-\frac{\sqrt{3} }{2} )$

This simplifies to

$2\theta=sin^{-1}(-\frac{\sqrt{3} }{2} )$

We look to the unit circle to see which values of theta give us a sin of -square root of 3 over 2. Those are:

$2\theta =\frac{5\pi }{6}$ and

$2\theta=\frac{7\pi }{6}$

Divide both sides by 2 in both of those equations to get that values of theta are:

$\theta=\frac{5\pi }{12},\frac{7\pi }{12}$

b. $tan(7a)=1$

Take the inverse tangent of both sides:

$tan^{-1}(tan(7a))=tan^{-1}(1)$

Taking the inverse tangent of the tangent on the left leaves us with just 7a. This simplifies to

$7a=tan^{-1}(1)$

We look to the unit circle to find which values of a give us a tangent of 1. They are:

$7\alpha =\frac{5\pi }{4},7\alpha =\frac{\pi }{4}$

Dibide each of those equations by 7 to find that the values of alpha are:

$\alpha =\frac{5\pi}{28},\frac{\pi}{28}$

c. $cos(3\beta)=\frac{1}{2}$

Take the inverse cosine of each side. The inverse cosine and cosine undo each other, leaving us with just 3beta on the left, just like in the previous problems. That simplifies to:

$3\beta=cos^{-1}(\frac{1}{2})$

We look to the unit circle to find the values of beta that give us the cosine of 1/2 and those are:

$3\beta =\frac{\pi}{6},3\beta =\frac{5\pi}{6}$

Divide each of those by 3 to find the values of beta are:

$\beta =\frac{\pi }{18} ,\frac{5\pi}{18}$

d. $sec3\alpha =-2$

Let's rewrite this in terms of a trig ratio that we are a bit more familiar with:

$\frac{1}{cos(3\alpha) } =\frac{-2}{1}$

We are going to simplify this even further by flipping both fraction upside down to make it easier to solve:

$cos(3\alpha)=-\frac{1}{2}$

Now we will take the inverse cos of each side (same as above):

$3\alpha =cos^{-1}(-\frac{1}{2} )$

We look to the unit circle one last time to find the values of alpha that give us a cosine of -1/2:

$3\alpha =\frac{7\pi}{6},3\alpha =\frac{11\pi}{6}$

Dividing both of those equations by 3 gives us

$\alpha =\frac{7\pi}{18},\frac{11\pi}{18}$

And we're done!!!

8 0

2 years ago

Mae has a number cube with 6 sides that are numbered 1 through 6. What is the probability that Mae will roll an odd number?

Stels [109]

Answer:

C) $P(E) = \frac{3}{6}$

The probability that Mae will roll an odd number

$P(E) = \frac{3}{6}$

Step-by-step explanation:

Step(i):-

Given that Mae has a number cube with 6 sides that are numbered 1 through 6.

n(S) = { 1,2,3,4,5,6,} = 6

Let 'E ' be the event of odd numbers

Mae will roll an odd number

n(E) = {1, 3, 5} = 3

Step(ii):-

The probability that Mae will roll an odd number

$P(E) = \frac{n(E)}{n(S)} = \frac{3}{6}$

$P(E) = \frac{3}{6}$

4 0

2 years ago

when a study is designed so that neither the subjects nor the experimenters know which subjects are in the treatment group and w

Nata [24]

(taken from a source)

double blind

Hope this helped!

:)

5 0

3 years ago

Read 2 more answers