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3 years ago

The margin of error in a confidence interval estimate accounts for:_________

Mathematics

1 answer:

dusya [7]3 years ago

3 0

Answer:

The percentage points within which the obtained results would differ from the real population value.

Step-by-step explanation:

The ideas of the margin of error and confidence interval are borne from the observed truth, which is that there is always room for error in any statistically computed figure such as a survey or poll. For example, the result of a poll could show an 80% confidnce interval with a margin of error of 3%. This simply means that if the poll was repeated, 80% of the real population would fall within an estimate of 3%.

Statistics are not always error proof. Sometimes, the results might even be totally different from the computed results. So, it is very important that room is made for the possibility of an error, and that is why we need the mrgin of error.

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2/5 + 3/8 - Adding fractions

m_a_m_a [10]

Answer:31/40

Step-by-step explanation:

To add you have to have a common denominator. To get that you can multiply each fraction by one in different ways. 2/5 *8/8= 16/40 and 3/8* 5/5= 15/40 and then add those two to give you 31/40.

5 0

3 years ago

Read 2 more answers

Copy the problems onto your paper, mark the givens and prove the statements asked. Given: ∠BTO ≅ ∠IWE WI ≅ BT , OW ≅ ET Prove: △

Varvara68 [4.7K]

Answer:

$\triangle BOT \cong \triangle IEW$

Step-by-step explanation:

We are given the following in the question:

$\angle BTO \cong \angle IWE\\WI \cong BT\\OT \cong EW$

We have to prove:

$\triangle BOT \cong \triangle IEW$

Proof:

$\text{In }\triangle BOT \text{ and } \triangle IEW$

we can write:

$\angle BTO = \angle IWE\text{ (Given)}\\WI \cong BT\text{ (Given)}\\OT \cong EW\text{ (Given)}$

Hence, the two triangle are congruent by SAS congruency rule.

$\triangle BOT \cong \triangle IEW$

The attached image shows the two triangle.

8 0

3 years ago

At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric

Marina CMI [18]

Answer:

a) The range is (1199, 1267)

b) The range is (1165, 1301)

c) The range is (1131, 1335)

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(1233,34)$

Where $\mu=1233$ and $\sigma=34$

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

Part a

For this case we can use the statement from the empirical rule "68% of the data falls within the first standard deviation (µ ± σ)", and we can find the limits like this:

$\mu -\sigma= 1233-34=1199$

$\mu +\sigma=1233+34=1267$

The range is (1199, 1267)

Part b

For this case we can use the statement from the empirical rule "95% of the data within the first two standard deviations (µ ± 2σ)", and we can find the limits like this:

$\mu -2\sigma= 1233-(2*34)=1165$

$\mu +2\sigma=1233+(2*34)=1301$

The range is (1165, 1301)

Part c

For this case we can use the statement from the empirical rule "99.7% of the data within the first three standard deviations (µ ± 3σ)" and that represent almost all the data, and we can find the limits like this:

$\mu -3\sigma= 1233-(3*34)=1131$