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natulia [17]
3 years ago
15

Technician A says when there is a delay or slip as the transmission shifts into any forward gear, a slipping rear clutch is indi

cated. Technician B says a slipping front or forward clutch is indicated if the shift for all forward gears is delayed. Who is correct?
Mathematics
1 answer:
blagie [28]3 years ago
8 0

Answer:

Technician B

Step-by-step explanation:

It is very important that any car is taking for a test drive and a road test is carried out to check for any sort of problem with the transmission of the car or any leakages that may be found in the hydraulic circuits.

Technician B is very correct because when the hydraulic circuits is leaking, the front or forward clutch tends to slip thereby causing the shift for all forward gears to be delayed

Also,the sticking of the spool into the body of the valve can also cause the problem to occur as well.

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Answer:

0.0903

Step-by-step explanation:

Given that :

The mean = 1450

The standard deviation = 220

sample mean = 1560

P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})

P(X > 1560) = P(Z > \dfrac{1560 - 1450}{220})

P(X > 1560) = P(Z > \dfrac{110}{220})

P(X> 1560) = P(Z > 0.5)

P(X> 1560) = 1 - P(Z < 0.5)

From the z tables;

P(X> 1560) = 1 - 0.6915

P(X> 1560) = 0.3085

Let consider the given number of weeks = 52

Mean \mu_x = np = 52 × 0.3085 = 16.042

The standard deviation =  \sqrt {n \time p (1-p)}

The standard deviation = \sqrt {52 \times 0.3085 (1-0.3085)}

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

Pr ( Y > 20) = P(Z > \dfrac{20.5 - 16.042}{3.3306})

Pr ( Y > 20) = P(Z >1 .338)

From z tables

P(Y > 20) \simeq 0.0903

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3 years ago
Which of the following points is on the graph of y=x^2-4x+5 ?
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Answer:

0,7

Step-by-step explanation:

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3 years ago
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ASAP!!!!!PLEASE HELP
ki77a [65]

\frac{distance}{time} =\frac{100/1609}{5/3600} = approx. 44.64\\answer D

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