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Lana71 [14]
3 years ago
13

All real numbers less than or equal to 9 and greater than or equal to 7 please hurry​

Mathematics
2 answers:
VashaNatasha [74]3 years ago
4 0

Answer:

7 \leq x \leq 9

Step-by-step explanation:

Let x represent the real numbers.

For the first part, all real numbers less than or equal to 9 in algebra is x \leq 9.

For the second part, all real numbers greater than or equal to 7 in algebra is x \geq 7.

To combine both inequalities, it would become 7 \leq x \leq 9.

Hope this helped! If not, please let me know! <3

ozzi3 years ago
4 0
It’s 7,8,9 because 8 is less than 9 and greater than 7 while 9 is equal to nine and 7 is equal to 7
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What is the vertex of the graph of #y=x^2+3x-4#?
borishaifa [10]
To find the x value of the vertex we do:

x = \frac{-b}{2a}
if your quadratic function is in the form ax² + bx + c = y

x = \frac{-3}{2(1)}
x = \frac{-3}{2}

Now we plug this x into the equation and solve for y.

y = (\frac{-3}{2}) ^{2} + 3( \frac{-3}{2} ) + 4
y = \frac{9}{4} -  \frac{9}{2} + 4
y = \frac{9}{4} - \frac{18}{4} + 4
y = \frac{-9}{4} + 4
y = \frac{-9}{4} + \frac{16}{4}
y = \frac{7}{4}

Your vertex (if my math is correct) is at ( \frac{-3}{2},  \frac{7}{4} )
8 0
3 years ago
Elena bikes 20 minutes each day for exercise. Write an equation to describe the relationship between her distance in miles, D, a
kompoz [17]

<u>Answer:</u>

The equation to describe the relationship between Elena distance:

a) D = 4.34 miles, b) D = 4.25 miles and c) 12D = M + 3N miles.

<u>Solution:</u>

Given, Elena bikes 20 minutes each day for exercise.  

We have to write an equation to describe the relationship between her distance in miles, D, and her biking speed, in miles per hour,  

We know that, distance travelled = speed \times time

a. At a constant speed of 13 miles per hour for the entire 20 minutes  

Her speed is 13 miles per hour.  

Then, distance D miles = 13 miles per hour \times 20 minutes

\mathrm{D}=13 \text { miles per hour } \times \frac{20}{60} \text { hours } \rightarrow \mathrm{d}=13 \times \frac{1}{3} \rightarrow \mathrm{d}=4.34 \text { miles approximately. }

b. At a constant speed of 15 minutes per hour for the first 5 minutes, then at 12 miles per hour for the last 15 minutes  

Now, total distance travelled = distance travelled with 15 mph + distance travelled with 12 mph

\begin{array}{l}{\mathrm{D}=15 \mathrm{mph} \times 5 \text { minutes }+12 \mathrm{mph} \times 15 \text { minutes }} \\\\ {\mathrm{D}=15 \mathrm{mph} \times \frac{5}{60} \text { hours }+12 \mathrm{mph} \times \frac{15}{60} \text { minutes }} \\\\ {\mathrm{D}=15 \times \frac{1}{12}+12 \times \frac{1}{4} \rightarrow \mathrm{D}=\frac{5}{4}+3 \rightarrow \mathrm{D}=3+1.25 \rightarrow \mathrm{D}=4.25 \mathrm{miles}}\end{array}

c. At a constant speed of M miles per hour for the first 5 minutes, then at N miles per hour for the last 15 minutes

Now, total distance travelled = distance travelled with M mph + distance travelled with N mph

D = M mph \times 5 minutes + N mph \times 15 minutes

\mathrm{D}=\mathrm{M} \mathrm{mph} \times \frac{5}{60} \text { hours }+\mathrm{N} \mathrm{mph} \times \frac{15}{60} \text { minutes }

\mathrm{D}=\mathrm{M} \times \frac{1}{12}+\mathrm{N} \times \frac{1}{4} \rightarrow \mathrm{D}=\frac{M}{12}+\frac{N}{4} \rightarrow \mathrm{D}=\frac{M}{12}+\frac{3 N}{12} \rightarrow 12 \mathrm{D}=\mathrm{M}+3 \mathrm{N} \text { miles }

Hence, a) D = 4.34 miles, b) D = 4.25 miles and c) 12D = M + 3N miles.

8 0
4 years ago
Look at the number pattern shown below:3 × 17 = 5133 × 167 = 5511333 × 1667 = 555111What will be 33333 × 166667?
dolphi86 [110]

Answer:

33333 x 166667 = 5555511111

I think that is the answer you wanted

Step-by-step explanation:

      166667

     x 33333

<u>5555511111 </u>

5 0
4 years ago
The measure of the supplement of an angle is three times the measure of the
gtnhenbr [62]
<h2>Answer:</h2>

<h3><em>x=45degrees</em></h3>

<h2>Step-by-step explanation:</h2>

Let the angle to be solved be x

Let the supplement/compliment by y

x+y=90 Complimentary angles add up to 90 degrees.

x+3y=180 Supplementary angles add up to 180 degrees, the other angle is thrice the other compliment.

Evaluating this as a system:

x+y=90 Isolate x:

x=90−y Input into the other equation:

(90−y)+3y=180 Combine like terms, isolate y and its coefficients:

2y=90 Isolate y

y=45 Input into the first equation:

x+45=90 Isolate x:

x=45degrees

5 0
3 years ago
Oh a number line what is the distance between -54 and 73
Ghella [55]

The correct answer is 127.

:)

5 0
4 years ago
Read 2 more answers
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