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olya-2409 [2.1K]
3 years ago
12

A bag contains purple marbles and blue marbles, 41 in total. The number of purple marbles is 4 less than 2 times the number of b

lue marbles. How many purple marbles are there?
Mathematics
1 answer:
Andreas93 [3]3 years ago
4 0

Answer:

There are 26 purple marbles in the bag.

Step-by-step explanation:

1) We have purple (p) and blue (b) marbles in a bag, and 41 marbles total so:

p+b = 41

2) we want to know how many purple marbles we have, so let's rearrange for p:

p = 41 - b

3) Our problem gives us an expression for the purple marbles in terms of the blue,  let's write it using math symbols instead of words:

<em>"The number of purple marbles is 4 less than 2 times the number of blue marbles."</em>

so: p = 2b - 4

3) Now we're going to plug this in (or substitute it) for our p in our first equation, and solve for b

p = 41 - b

2b - 4 = 41 - b     (substitution)

2b = 45 - b         ( add 4 to both sides)

3b = 45               (add b to both sides)

b = 15                  (divide both sides by 3)

4, last step!)

Now we know we have 15 blue marbles, that's great! But we still want to know how many purple marbles we have.

41- 15 = 26 purple marbles

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In a clinical trial of 268 subjects treated with a​ drug, 11​% of the subjects reported dizziness. The margin of error is plus o
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Answer:

\hat p =0.11 represent the proportion estimated of subjects reported with dizziness

n = 268 represent the random sample selected

\hat q = 1-\hat p = 1-0.11= 0.89 represent the proportion of subjects No reported with dizziness

E= 0.04 = 4% represent the margin of error for the confidence interval

\alpha= 1-0.90 =0.1 and this value represent the significance level of the test or the probability of error type I

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The margin of error is given by:

ME= z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

Lower= 0.11-0.04 = 0.07

Upper= 0.11+0.04 = 0.15

And for this case we have the following info:

\hat p =0.11 represent the proportion estimated of subjects reported with dizziness

n = 268 represent the random sample selected

\hat q = 1-\hat p = 1-0.11= 0.89 represent the proportion of subjects No reported with dizziness

E= 0.04 = 4% represent the margin of error for the confidence interval

\alpha= 1-0.90 =0.1 and this value represent the significance level of the test or the probability of error type I

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Answer:

F=201.2\°

Step-by-step explanation:

we know that

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For C=94\°

substitute in the formula and solve for F

94=\frac{5}{9}[F-32]

(\frac{9}{5})*94=[F-32]

F=(\frac{9}{5})*94+32

F=201.2\°

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Answer:

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Step-by-step explanation:

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