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3 years ago

A = 40, c = 41, b = ?

Mathematics

1 answer:

just olya [345]3 years ago

3 0

Well, with a little bit of work with the Pythagorean Theorem, which in a right triangle, which this is, where the sum of the squares of the lengths of the legs is equal to the square of the length of the hypotenuse, and the equation is a^2 + b^2 = c^2, but you know what A and C is, therefore, you would have to find B. Therefore, you will need to find B, and the Hypotenuse, and the hypotenuse is always the opposite of the right angle, and is always the longest side of the triangle, which is C, therefore, the hypotenuse is 41. You need to find B, like I stated before. B is a leg, therefore you will do 1600 + ____ = 1681 (I found 1600 by squaring 40, which is A, and I found 1681 by squaring 41, which is C.) Therefore, what gives you 81? 9! Your answer is 9!

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3 years ago

What is the solution of the equation? 4(y + 2) =32

ehidna [41]

Hey there!
For the left side, we are going to use the distributive property, which means:
a(b+c) = ab+ac
Therefore, we have:

4y + 8 = 32

Subtract 8 from both sides.

4y = 24

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I hope this helped you! :)

6 0

4 years ago

Read 2 more answers

(x-1/x ²-4) + (1/x-2)

kodGreya [7K]

Answer:

(2x+1)/(x^2 -4)

Step-by-step explanation:

When you add fractions (or rational expressions) you need to express each of them over a common denominator, so you can add the numerators. (Parentheses or other grouping symbols are required.)

$\dfrac{x-1}{x^2-4}+\dfrac{1}{x-2}=\dfrac{x-1}{(x-2)(x+2)}+\dfrac{(1)(x+2)}{(x-2)(x+2)} \qquad\text{now we have a common denominator}\\\\=\dfrac{(x-1)+(x+2)}{(x-2)(x+2)}=\dfrac{2x+1}{(x-2)(x+2)}=\dfrac{2x+1}{x^2-4}$

You factor the denominator on the left so you can see what factors are missing from the denominator on the right.

<em>Numerical example</em>

Suppose you want to add the fractions 4/15 and 3/5. You would factor the denominator 15 into 3·5, so you can see that the fraction 3/5 needs to be multiplied by (3/3) in order to give it a denominator of 15. Once the two fractions have a common denominator, you can add their numerators.

4/15 + 3/5 = 4/15 + (3/5)(3/3)

= 4/15 + 9/15

= (4+9)/15 = 13/15

_____

<em>Comment on grouping symbols</em>

When a rational expression is typeset, the division bar of the fraction identifies the numerator and the denominator:

$\dfrac{x-1}{x^2-4}$

When you write it in plain text as ...

x - 1/x^2 -4

this becomes a 3-term expression:

(x) -(1/x^2) -(4)

which is very different from what you may intend. In order to match the original typeset expression, parentheses must be added to show the group in the numerator and the group in the denominator:

(x -1)/(x^2 -4)

The same holds for exponents. The superscript position in a typeset expression tells you what the exponent is. When you write the same thing in plain text, parentheses are needed to show the exponent group.

$3^{x-1}$ = 3^(x -1) ≠ 3^x -1

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4 years ago

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The cost of the bench b=$29

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That would make it b=29-4, hence the option C

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3 years ago