Answer:
2. Cost of six books
3. Cost of one book
Step-by-step explanation:
I don't know about the rest though.
Answer:
0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.
The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.
Step-by-step explanation:
Assume that the probability of a defective computer component is 0.02. Components are randomly selected. Find the probability that the first defect is caused by the seventh component tested.
First six not defective, each with 0.98 probability.
7th defective, with 0.02 probability. So

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.
Find the expected number and variance of the number of components tested before a defective component is found.
Inverse binomial distribution, with 
Expected number before 1 defective(n = 1). So

Variance is:

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.
X = 4 because 1 over 24 times 4 is 4 over 24 which is converted to 1 over 6
We can figure this out using the explicit formula.

n represents the term we are looking for.
f(1) represents the first term in the sequence, which in this case, is 7.
d represents the common difference, which in this case, is +3.
f(n) = 7 + 3(n - 1)
f(n) = 7 + 3n - 3
f(n) = 4 + 3n
Now, we can input 214 for n and solve.
f(214) = 4 + 3(214)
f(214) = 4 + 642
f(214) = 646
The 214th term in this sequence is 646.
Answer: He is paid $90 last weekend.
Step-by-step explanation:
Since we have given that
Amount he earns per hour = $6
If he works on Saturday, he is paid time and a quarter .
Amount would be

If he works on Sunday, he is paid time and a half.
Amount would be

Number of hours he worked on Saturday = 6 hours
Number of hours he worked on Sunday = 5 hours
So, Total amount he is paid last weekend altogether is given by

Hence, he is paid $90 last weekend.