You have to solve for 1 variable
I'm pretty sure they want 4y and not just y becaseu taht is too easy
-6x+4y=33
5x+18y=29
solve for 1 variable
may be messy
-6x+4y=33
add 6x both sides
4y=33+6x
divide both sides by 4
y=(33+6x)/4
sub that for y in other equation
5x+18((33+6x)/4)=29
5x+9(33+6x)/2=29
5x+(297+54x)/2=29
(10x/2)+(297+54x)/2=29
times both sides by 2
10x+297+54x=58
297+64x=58
minus 297 both sides
64x=-239
divide both sides by 64
x=-239/64
sub back
y=(33+6x)/4
y=(33+6(-239/64))/4
y=(33-717/32)/4
y=(1056/32-717/32)/4
y=(339/32)/4
y=339/128
the solution is
you can graph it and check if you want
Answer:
123
Step-by-step explanation:
if the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadth
Answer:
3x-2
Step-by-step explanation:
-22, LA and LB are complementary. Find mzA and mzB. For pro 21. mzA = 3x 22. mzA = 2x -5 mzB = 5x + 2 90 SR 90 For proble s 21- 23. mzA = x mzB = 3x 90 6 2, ZA and LB Find m
Answer:
B: -6+2i
Step-by-step explanation:
- 3i + (-6 - i) = ⇒ open parenthesis
- 3i - 6 - i = ⇒ simplify
- -6 + 2i ⇒ answer in standard form of a+bi
