A study on students drinking habits wants to determine the true average number of alcoholic drinks all uf underclassmen students have in a one week period. We know from preliminary studies that the standard deviation is around 2. 8. How many students should be sampled to be within 1. 5 drink of population mean with 90% probability?.
1 answer:
Answer: 16
Step-by-step explanation:
Standard deviation is 2
Margin error for the problem is 1
Probability 95%, that means thet the siginficance level α is 1 – p
α = 1 – 0.95 = 0.05
margin of error (ME) can be defined as follows
ME = Z(α/2) * standard deviation/ √n
Where n is the sample size
Z(0.05/2) = Z(0.025)
Using a z table Z = 1.96
Now, replacing in the equation and find n
1 = 1.96 * 2/ √n
1 = 3.92 / √n
√n = 3.92
n = 3.92^2
n = 15.36 = 16
i hope this work for you
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